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这里有一些有趣的东西！该merge声明工作正常。但是当值匹配时，它不会按预期将状态更新为“B”。知道为什么吗？

merge into bbbt b 
using (select bank,ifsc,branch,
              center,district,state,
              address,status 
         from rtgbrn_temp 
        where ifsc in (SELECT ifsc 
                         FROM rtgbrn_temp 
                        MINUS 
                       SELECT ifsc_code 
                         FROM bbbt)
        ) x
   on (x.ifsc = b.ifsc_code)
 when matched then 
   update 
      set rtgs_stat = 'B' 
    where (x.ifsc=b.ifsc_code)
 when not matched then 
   insert (bankid,benbrn_code,brn_name,
           brn_addr,brn_loc,brn_stat,
           brn_city,coun_code,
           remarks,ifsc_code,
           rtgs_stat)
   values (substr(x.ifsc,1,4), substr(x.ifsc,5), 
           x.branch, x.address, x.district, 
           x.state, x.center,'IN', x.bank, x.ifsc,'R');

[也尝试使用重复更新，但无法使用错误]

SQL Error: ORA-00933: SQL command not properly ended!

insert into bbbt(bankid,benbrn_code,brn_name,brn_addr,brn_loc,brn_stat,brn_city,coun_code,remarks,ifsc_code,rtgs_stat)
select substr(x.ifsc,1,4), substr(x.ifsc,5), x.branch, x.address, x.district, x.state, x.center,'IN', x.bank, x.ifsc,'R' from 
(select bank,ifsc,branch,center,district,state,address,status from rtgbrn_temp where ifsc in (SELECT ifsc FROM rtgbrn_temp MINUS SELECT ifsc_code FROM bbbt))x
ON DUPLICATE KEY UPDATE rtgs_stat = 'B';

请分享您的知识，谢谢！

4

2 回答 2

2

查询中的值无法匹配。

仔细查看查询的这一部分。

select ..., ifsc, .....
from rtgbrn_temp 
where ifsc in (........
               .........
               MINUS 
               SELECT ifsc_code 
               FROM bbbt )

此查询检索不等于表中任何ifsc代码的代码。 然后查询使用这些代码来匹配记录：ifsc_codebbbt

 on (x.ifsc = b.ifsc_code)

以上等价于

on (subquery.ifsc = bbbt.ifsc_code)

因为x是子查询的别名，b是bbbt表名。

想一想....
子查询只返回不等于任何值的代码bbbt.ifsc_code
这意味着条件subquery.ifsc = bbbt.ifsc_code 永远不匹配。

于 2013-11-03T12:16:19.113 回答
0

编辑代码：

merge into bbbt b using (select bank,ifsc,branch,center,district,state,address,status from rtgbrn_temp) x
on (x.ifsc = b.ifsc_code)
when matched then update set rtgs_stat = 'B'
when not matched then insert (bankid,benbrn_code,brn_name,brn_addr,brn_loc,brn_stat,brn_city,coun_code,remarks,ifsc_code,rtgs_stat)
values (substr(x.ifsc,1,4), substr(x.ifsc,5), x.branch, x.address, x.district, x.state, x.center,'IN', x.bank, x.ifsc,'R');
于 2013-11-04T07:04:35.397 回答