28

我有一个包含 2 列的数据框，GL并且GLDESC想要添加一个KIND基于 column 内部的一些数据调用的第三列GLDESC。

数据框如下：

      GL                             GLDESC
1 515100         Payroll-Indir Salary Labor
2 515900 Payroll-Indir Compensated Absences
3 532300                           Bulk Gas
4 539991                     Area Charge In
5 551000        Repairs & Maint-Spare Parts
6 551100                 Supplies-Operating
7 551300                        Consumables

对于数据表的每一行：

  • 如果在字符串GLDESC中的任何位置包含单词，那么我想成为PayrollKINDPayroll
  • 如果在字符串GLDESC中的任何位置包含单词，那么我想成为GasKINDMaterials
  • 在所有其他情况下，我想KIND成为Other

我在 stackoverflow 上查找了类似的示例，但找不到任何示例，还查找了Rswitch、grep、apply 和正则表达式上的假人，以尝试仅匹配GLDESC列的一部分，然后KIND用帐户类型填充列，但无法让它起作用。

4

2 回答 2

30

由于您只有两个条件，因此可以使用嵌套ifelse：

#random data; it wasn't easy to copy-paste yours  
DF <- data.frame(GL = sample(10), GLDESC = paste(sample(letters, 10), 
  c("gas", "payroll12", "GaSer", "asdf", "qweaa", "PayROll-12", 
     "asdfg", "GAS--2", "fghfgh", "qweee"), sample(letters, 10), sep = " "))

DF$KIND <- ifelse(grepl("gas", DF$GLDESC, ignore.case = T), "Materials", 
         ifelse(grepl("payroll", DF$GLDESC, ignore.case = T), "Payroll", "Other"))

DF
#   GL         GLDESC      KIND
#1   8        e gas l Materials
#2   1  c payroll12 y   Payroll
#3  10      m GaSer v Materials
#4   6       t asdf n     Other
#5   2      w qweaa t     Other
#6   4 r PayROll-12 q   Payroll
#7   9      n asdfg a     Other
#8   5     d GAS--2 w Materials
#9   7     s fghfgh e     Other
#10  3      g qweee k     Other

编辑 2016 年 10 月 3 日（..收到比预期更多的关注后）

处理更多模式的一种可能解决方案是遍历所有模式，并在匹配时逐步减少比较量：

ff = function(x, patterns, replacements = patterns, fill = NA, ...)
{
    stopifnot(length(patterns) == length(replacements))

    ans = rep_len(as.character(fill), length(x))    
    empty = seq_along(x)

    for(i in seq_along(patterns)) {
        greps = grepl(patterns[[i]], x[empty], ...)
        ans[empty[greps]] = replacements[[i]]  
        empty = empty[!greps]
    }

    return(ans)
}

ff(DF$GLDESC, c("gas", "payroll"), c("Materials", "Payroll"), "Other", ignore.case = TRUE)
# [1] "Materials" "Payroll"   "Materials" "Other"     "Other"     "Payroll"   "Other"     "Materials" "Other"     "Other"

ff(c("pat1a pat2", "pat1a pat1b", "pat3", "pat4"), 
   c("pat1a|pat1b", "pat2", "pat3"), 
   c("1", "2", "3"), fill = "empty")
#[1] "1"     "1"     "3"     "empty"

ff(c("pat1a pat2", "pat1a pat1b", "pat3", "pat4"), 
   c("pat2", "pat1a|pat1b", "pat3"), 
   c("2", "1", "3"), fill = "empty")
#[1] "2"     "1"     "3"     "empty"
于 2013-11-02T22:52:13.653 回答
1

我个人喜欢按索引匹配。您可以遍历grep新标签，以获取部分匹配的索引，然后将其与查找表一起使用以简单地重新分配值。

如果您想创建新标签，请使用命名向量。

DF <- data.frame(GL = sample(10), GLDESC = paste(sample(letters, 10),
  c(
    "gas", "payroll12", "GaSer", "asdf", "qweaa", "PayROll-12",
    "asdfg", "GAS--2", "fghfgh", "qweee"
  ), sample(letters, 10),
  sep = " "
))


lu <- stack(sapply(c(Material = "gas", Payroll = "payroll"), grep, x = DF$GLDESC, ignore.case = TRUE))

DF$KIND <- DF$GLDESC
DF$KIND[lu$values] <- as.character(lu$ind)
DF$KIND[-lu$values] <- "Other"

DF
#>    GL         GLDESC     KIND
#> 1   6        x gas f Material
#> 2   3  t payroll12 q  Payroll
#> 3   5      a GaSer h Material
#> 4   4       s asdf x    Other
#> 5   1      m qweaa y    Other
#> 6  10 y PayROll-12 r  Payroll
#> 7   7      g asdfg a    Other
#> 8   2     k GAS--2 i Material
#> 9   9     e fghfgh j    Other
#> 10  8      l qweee p    Other

由reprex 包于 2021-11-13 创建(v2.0.1)

于 2021-11-13T15:02:00.570 回答