python - 如何将一串数字变成一个列表

Question

如何将主要包含数字的字符串拆分为列表？我试过str.split()了，但由于每个数字都用逗号分隔，我无法将字符串转换为整数列表。例如：

a='text,2, 3, 4, 5, 6'

当我这样做split时

b=['text,2,', '3,', '4,', '5,', '6']

有没有办法将整数隔离到一个列表中？

Answer 1

使用regex：

>>> a = 'text,2, 3, 4, 5, 6' 
>>> import re
>>> re.findall(r'\d+', a)
['2', '3', '4', '5', '6']

---

str.isdigit使用和列表理解的非正则表达式解决方案：

>>> [y for y in  (x.strip() for x in a.split(',')) if y.isdigit()]
['2', '3', '4', '5', '6']

---

如果您希望将字符串转换为整数，则只需调用int()列表中的项目。

>>> import re
>>> [int(m.group()) for m in re.finditer(r'\d+', a)]
[2, 3, 4, 5, 6]

>>> [int(y) for y in  (x.strip() for x in a.split(',')) if y.isdigit()]
[2, 3, 4, 5, 6]

Answer 2

Here is a solution that doesn't use Regex:

>>> a='text,2, 3, 4, 5, 6'
>>> # You could also do "[x for x in (y.strip() for y in a.split(',')) if x.isdigit()]"
>>> # I like this one though because it is shorter
>>> [x for x in map(str.strip, a.split(',')) if x.isdigit()]
['2', '3', '4', '5', '6']
>>> [int(x) for x in map(str.strip, a.split(',')) if x.isdigit()]
[2, 3, 4, 5, 6]
>>>