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我有一个大文本文件，其中包含数千个以空格分隔的数字。我想使用 Java FileChannel 读取每个数字。

我能够使用此处提到的第一种方法读取文件：http: //howtodoinjava.com/2013/05/01/3-ways-to-read-files-using-java-nio/但我不确定如何我会读取两位、三位和四位数字的每个数字。

我的代码：

public static void main(String args[]) {

    try
    {
        String file_name="abc.txt";
        RandomAccessFile input_file = new RandomAccessFile(file_name,"r");
        FileInputStream in = new FileInputStream(file_name);
        FileChannel ch = in.getChannel();
        FileChannel inChannel = input_file.getChannel();
        long file_size = inChannel.size();
        ByteBuffer buffer = ByteBuffer.allocate((int) file_size);

        Charset cs = Charset.forName("ASCII");
        // inChannel.read(buffer);

        int rd;
        while ( (rd = ch.read( buffer )) != -1 ) 
        {
            buffer.rewind();
            System.out.println("String read: ");
            CharBuffer chbuf = cs.decode(buffer);

            for ( int i = 0; i < chbuf.length(); i++ ) 
            {

               System.out.print(chbuf.get());
            }
            buffer.clear();
            inChannel.close();
            input_file.close();
        }
    }
    catch (IOException exc){}

} }

4

1 回答 1

1

我已经修改了您的代码以分别隔离每个数字（不需要太多修改）： 

import java.io.FileInputStream;
import java.io.IOException;
import java.io.RandomAccessFile;
import java.nio.ByteBuffer;
import java.nio.CharBuffer;
import java.nio.IntBuffer;
import java.nio.channels.FileChannel;
import java.nio.charset.Charset;
import java.util.ArrayList;

public class ReadFile {

    public static void main(String args[]) {

        try
        {   
            String s; 
            Integer I;
            String file_name="C:/Users/User/test.txt";
            RandomAccessFile input_file = new RandomAccessFile(file_name,"r");
            FileInputStream in = new FileInputStream(file_name);
            FileChannel ch = in.getChannel();
            FileChannel inChannel = input_file.getChannel();
            long file_size = inChannel.size();
            ByteBuffer buffer = ByteBuffer.allocate((int) file_size);

            Charset cs = Charset.forName("ASCII");
            ArrayList<Character> character = new ArrayList<Character>();
            // inChannel.read(buffer);

            int rd;
            while ( (rd = ch.read( buffer )) != -1 ) 
            {
                buffer.rewind();

                CharBuffer chbuf = cs.decode(buffer);

                System.out.println("ASCII values read: ");

                System.out.println();

                     for ( int i = 0; i < chbuf.length(); i++ ) 
                    {

                        int j = chbuf.get();

                        character.add((char)j);

                        System.out.println("j("+i+"): "+j+" ");

                    }

                     System.out.println();

                     System.out.println("Chars they represent: ");

                     System.out.println();

                     for ( int i = 0; i < character.size(); i++ ) 
                        {

                        System.out.println("character("+i+"): "+character.get(i)+" ");
                        System.out.println();
                        s = character.get(i).toString();
                        if(!(s.equals(" ")||s.equals("\r")))
                            {
                            System.out.println("s("+i+"): "+s+" ");
                            System.out.println();
                            System.out.println("s("+i+").length(): "+s.length()+" ");
                            System.out.println();
                            I = new Integer(s);
                            System.out.println("I("+i+"): "+I+" ");
                            System.out.println();
                            }
                        }

                buffer.clear();
                inChannel.close();
                input_file.close();
            }
        }
        catch (IOException exc){}
    }
}
于 2013-11-02T21:38:25.510 回答