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我正在开发一个文档管理系统，但我似乎被卡住了。

该数据库包含所有文档编号（唯一）及其所有修订版（ABC 等）。将文档发送给客户时，我使用传输文件（文档 1234，修订版 B 与传输文件 6 一起发送给客户 XYZ）。

现在，团队希望有一个概览（表格），他们可以在其中查看每个文档的最新修订版和最新修订版，发送给客户 XYZ。像这样的东西：

    ---------------------------------------------------------------------------------------
    | Documents  || Latest Revision || Last sent Revision                                  |
    |            || revision        || revision   | transmittalnr   | sent To     | Reason |
    -------------||-----------------||- ---------------------------------------------------
    |            ||                 ||            |                 |             |        |
    | [docnrlab] || [revision]      || [revision] | [transmittalnr] | [userto_id] | [rsn]  |
    ---------------------------------------------------------------------------------------

我一直在尝试通过一个查询来实现它，但由于我不是专家，我似乎没有完成它。我得到了什么（通过反复试验，这可能不是构建复杂查询的最佳方式）

    /* all docs with al their revis */
    SELECT * , revisiondate, docrevisions.id
    FROM docrevisions
    ORDER BY doc_id



    /* for each doc: give the latest revi, which has a transmittal */
    SELECT * , MAX( revisiondate ), docrevisions.id AS revi_id, transmittals2revisions . *
    FROM docrevisions
    LEFT JOIN transmittals2revisions ON docrevisions.id = transmittals2revisions.revisions_id
    LEFT JOIN transmittals ON transmittals2revisions.transmittal_id = transmittals.id
    WHERE transmittals.id IS NOT NULL
    GROUP BY doc_id



    /* testing */
    SELECT docrevisions.id AS sent, docrevisions.id AS unsent, documents.docnrlab
    FROM docrevisions
    INNER JOIN transmittals2revisions AS t2revi1 ON sent = t2revi1.revisions_id
    INNER JOIN transmittals2revisions AS t2revi2 ON unsent = t2revi2.revisions_id
    INNER JOIN documents ON docrevisions.doc_id = documents.id
    WHERE t2revi1.revisions_id IS NOT NULL
    AND t2revi2.revisions_id IS NULL
    GROUP BY doc_id
    ORDER BY docrevisions.doc_id ASC

在另一个查询中，我使用别名，我认为这对我的问题有帮助，但我不知道如何找到正确的：

    $sql = "SELECT trm.*, userfrom.lastname AS UserFrom, userto.lastname AS UserTo 
            FROM transmittals AS trm 
            LEFT JOIN users AS userfrom ON userfrom.id = trm.userfrom_id
            LEFT JOIN users AS userto ON userto.id = trm.userto_id";

下面是涉及的数据表的结构

    CREATE SCHEMA IF NOT EXISTS `docguard` DEFAULT CHARACTER SET utf8 ;
    USE `docguard` ;


    -- -----------------------------------------------------
    -- Table `docguard`.`documents`
    -- -----------------------------------------------------
    CREATE  TABLE IF NOT EXISTS `docguard`.`documents` (
      `id` INT(10) NOT NULL AUTO_INCREMENT ,
      `docnrsupplier` TEXT NULL DEFAULT NULL ,
      `docnrlab` TEXT NULL DEFAULT NULL ,
      `docnrclient` TEXT NULL DEFAULT NULL ,
      `title1` TEXT NULL DEFAULT NULL ,
      `title2` TEXT NULL DEFAULT NULL ,
      `title3` TEXT NULL DEFAULT NULL ,
      `title4` TEXT NULL DEFAULT NULL ,
      `docsize_id` INT(10) NULL DEFAULT NULL ,
      `docstate_id` INT(10) NULL DEFAULT NULL ,
      `docformat_editable_id` INT(10) NULL DEFAULT NULL ,
      `docformat_noneditable_id` INT(10) NULL DEFAULT '0' ,
      `file_editable` TEXT NULL DEFAULT NULL ,
      `file_noneditable` TEXT NULL DEFAULT NULL ,
      `doccat_id` INT(10) NULL DEFAULT NULL ,
      `docphase_id` INT(10) NULL DEFAULT NULL ,
      `doctype_id` INT(10) NULL DEFAULT NULL ,
      `company_id` INT(10) NULL DEFAULT NULL ,
      `docrevisions_id` INT(10) NOT NULL ,
      PRIMARY KEY (`id`) ,
      INDEX `fk_documents_docrevisions_idx` (`docrevisions_id` ASC) )
    ENGINE = MyISAM
    AUTO_INCREMENT = 778
    DEFAULT CHARACTER SET = utf8;


    -- -----------------------------------------------------
    -- Table `docguard`.`docrevisions`
    -- -----------------------------------------------------
    CREATE  TABLE IF NOT EXISTS `docguard`.`docrevisions` (
      `id` INT(10) NOT NULL AUTO_INCREMENT ,
      `doc_id` INT(10) NOT NULL ,
      `revision` TEXT NOT NULL ,
      `revisiondate` DATE NULL DEFAULT NULL ,
      `user_id` INT(10) NULL DEFAULT NULL ,
      `transmittals2revisions_id` INT(10) NOT NULL ,
      PRIMARY KEY (`id`) ,
      INDEX `fk_docrevisions_transmittals2revisions1_idx` (`transmittals2revisions_id` ASC) )
    ENGINE = MyISAM
    AUTO_INCREMENT = 1199
    DEFAULT CHARACTER SET = utf8;


    -- -----------------------------------------------------
    -- Table `docguard`.`transmittals2revisions`
    -- -----------------------------------------------------
    CREATE  TABLE IF NOT EXISTS `docguard`.`transmittals2revisions` (
      `id` INT(10) NOT NULL AUTO_INCREMENT ,
      `transmittal_id` INT(10) NOT NULL ,
      `revisions_id` INT(10) NULL DEFAULT NULL ,
      `quantity` TINYINT(2) NOT NULL DEFAULT '1' ,
      `rsn` TINYINT(1) NOT NULL DEFAULT '0' ,
      PRIMARY KEY (`id`) )
    ENGINE = MyISAM
    AUTO_INCREMENT = 607
    DEFAULT CHARACTER SET = utf8;


    -- -----------------------------------------------------
    -- Table `docguard`.`transmittals`
    -- -----------------------------------------------------
    CREATE  TABLE IF NOT EXISTS `docguard`.`transmittals` (
      `id` INT(10) NOT NULL AUTO_INCREMENT ,
      `transmittalnr` TEXT NOT NULL ,
      `userfrom_id` INT(10) NULL DEFAULT NULL ,
      `userto_id` INT(10) NULL DEFAULT NULL ,
      `shippingtimestamp` DATE NULL DEFAULT NULL ,
      `replybeforetimestamp` DATE NULL DEFAULT NULL ,
      `note` TEXT NULL DEFAULT NULL ,
      `tempname` TINYINT(1) NOT NULL DEFAULT '0' ,
      `transmittals2revisions_id` INT(10) NOT NULL ,
      PRIMARY KEY (`id`) ,
      INDEX `fk_transmittals_transmittals2revisions1_idx` (`transmittals2revisions_id` ASC) )
    ENGINE = MyISAM
    AUTO_INCREMENT = 52
    DEFAULT CHARACTER SET = utf8;

我为这篇长文道歉，但我希望有人能帮助我或为我指明正确的方向。提前致谢！

4

2 回答 2

2

在这里，您需要执行两个分析查询：

  1. 要在所有选定文档的修订中查找具有最新日期的修订：

    SELECT dr.doc_id, dr.id, MAX(dr.revisiondate)
  FROM docrevisions dr
  GROUP BY dr.doc_id

  2. 要在传输给用户 XYZ 的所有选定文档的修订中查找具有最新日期的修订：

    SELECT dr.doc_id, dr.id, MAX(tr.shippingtimestamp)
  FROM transmittals2revisions t2r, transmittals tr, docrevisions dr
  WHERE t2r.transmittal_id = tr.id
    AND dr.id = t2r.revisions_id
  GROUP BY dr.doc_id

因此，我们可以将它们组合成一个查询：

     SELECT d.id doc_id, 
            rl.id last_revision_id, 
            rlt.id last_trans_revision_id, 
            rlt.transmittalnr,
            rlt.userto_id,
            rlt.rsn
      FROM documents d,
      (
       SELECT dr.doc_id, dr.id, MAX(dr.revisiondate)
         FROM docrevisions dr
         GROUP BY dr.doc_id
      ) rl,
      (
       SELECT dr.doc_id, dr.id, 
              tr.transmittalnr, tr.userto_id,
              t2r.rsn,
              MAX(tr.shippingtimestamp)
         FROM transmittals2revisions t2r, 
              transmittals tr, 
              docrevisions dr
         WHERE t2r.transmittal_id = tr.id
           AND dr.id = t2r.revisions_id
           AND tr.userfrom_id = 1
         GROUP BY dr.doc_id
      ) rlt
      where d.id = rl.doc_id 
        AND d.id = rlt.doc_id;

其中d.id - 文档，rl.id - 最后修订版，rlt.id - 最后传输的修订版。据我了解shippingtimestamp - 传输时间。

于 2013-11-02T14:47:12.640 回答
0

@Konstantin Kiselev 为我指出了正确的解决方案，非常感谢他。我将在这里写下我是如何用他的建议解决我的问题的：

  1. 在所有选定文档的修订中查找具有最新日期的修订 - 从上面更改，因为我也需要实际修订（ABC-etc）：

    SELECT d.docnrlab, dr.*
FROM documents d, docrevisions AS dr
INNER JOIN 
(
    SELECT dr.id, dr.doc_id, MAX( revisiondate ) AS revisiondate
    FROM docrevisions AS dr
    GROUP BY doc_id
) 
AS CurrentRevision 
    ON CurrentRevision.doc_id = dr.doc_id
    AND CurrentRevision.revisiondate = dr.revisiondate
WHERE d.id = dr.doc_id

  2. 在传输给用户 XYZ 的所有选定文档的修订中查找具有最新日期的修订 - 我没有提到可能根本没有发送文档。

    SELECT dr.id, dr.doc_id, dr.revision , MAX( revisiondate ), 
    tr.transmittalnr, tr.userto_id,
    t2r.rsn,
    MAX(tr.shippingtimestamp)
FROM docrevisions dr
LEFT JOIN transmittals2revisions AS t2r ON dr.id = t2r.revisions_id
LEFT JOIN transmittals AS tr ON t2r.transmittal_id = tr.id
/*WHERE tr.id IS NOT NULL*/
GROUP BY doc_id

/* 现在都在一起了 */

SELECT d.id doc_id, 
    d.docnrlab doc_nr_lab,
    rl.id last_revision_id, 
    rl.revision last_revision,
    rlt.id last_trans_revision_id, 
    rlt.revision last_trans_revision,
    rlt.transmittalnr,
    rlt.userto_id,
    rlt.rsn
FROM documents d,
    (
        SELECT d.docnrlab, dr.*
        FROM documents d, docrevisions AS dr
        INNER JOIN 
        (
            SELECT dr.id, dr.doc_id, MAX( revisiondate ) AS revisiondate
            FROM docrevisions AS dr
            GROUP BY doc_id
        ) 
        AS CurrentRevision 
            ON CurrentRevision.doc_id = dr.doc_id
            AND CurrentRevision.revisiondate = dr.revisiondate
        WHERE d.id = dr.doc_id
    ) rl,
    (
        SELECT dr.id, dr.doc_id, dr.revision , MAX( revisiondate ), 
            tr.transmittalnr, tr.userto_id,
            t2r.rsn,
            MAX(tr.shippingtimestamp)
        FROM docrevisions dr
        LEFT JOIN transmittals2revisions AS t2r ON dr.id = t2r.revisions_id
        LEFT JOIN transmittals AS tr ON t2r.transmittal_id = tr.id
        /*WHERE tr.id IS NOT NULL*/
        GROUP BY doc_id
    ) rlt
WHERE d.id = rl.doc_id 
    AND d.id = rlt.doc_id;
于 2013-11-02T17:24:03.793 回答