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我正在尝试通过过滤其中一个关系中的列来批量删除关联表中的对象。我在 SQLAlchemy 中使用以下调用进行删除

db.session.query(UserPaper).join(Paper, (UserPaper.paper_id ==
Paper.id)).filter(UserPaper.user_id == user.id).filter(Paper.journal_id 
== journal.id).delete()

并导致以下错误

OperationalError: (OperationalError) (1054, "Unknown column 'papers.journal_id' 
in 'where clause'") 'DELETE FROM userpapers WHERE userpapers.user_id = %s AND
papers.journal_id = %s' (1L, 1L)

最后没有删除，SQLAlchemy 查询是

SELECT userpapers.user_id AS userpapers_user_id, userpapers.paper_id AS 
userpapers_paper_id, userpapers.created AS userpapers_created, 
userpapers.read_at AS userpapers_read_at, userpapers.score AS userpapers_score
FROM userpapers JOIN papers ON userpapers.paper_id = papers.id
WHERE userpapers.user_id = :user_id_1 AND papers.journal_id = :journal_id_1

哪个是对的。从错误中我可以看到，当我附加delete()到查询时，SQL 语句的连接部分会丢失，并且数据库显然不知道如何找到该papers.journal_id列。我不明白为什么会这样？

这是我的 ORM 对象的设置

class User(db.Model):
    __tablename__ = 'users'

    id = db.Column(db.Integer, primary_key=True)
    email = db.Column(db.String(255), unique=True)
    papers = db.relationship("UserPaper", backref=db.backref('users'), lazy='dynamic')

class Paper(db.Model):
    __tablename__ = 'papers'

    id = db.Column(db.Integer, primary_key = True)
    title = db.Column(db.String(1024))
    journal_id = db.Column(db.Integer, db.ForeignKey('journals.id'))

class UserPaper(db.Model):
    __tablename__ = 'userpapers'

    user_id = db.Column(db.Integer, db.ForeignKey('users.id'), primary_key=True)
    paper_id = db.Column(db.Integer, db.ForeignKey('papers.id'), primary_key=True)
    paper = db.relationship("Paper", backref=db.backref('user_paper'))
    read_at = db.Column(db.DateTime)
    score = db.Column(db.Integer)

class Journal(db.Model):
    __tablename__ = 'journals'

    id = db.Column(db.Integer, primary_key = True)
    title = db.Column(db.String(100), index = True, unique = True)
    papers = db.relationship('Paper', backref = 'journal', lazy = 'dynamic')
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1 回答 1

4

我在使用 MySQL 5.6 的 SQLALchemy 0.9 中遇到了同样的问题。它看起来像一个错误/限制。但是，获得 arround 的一种更好的方法（与创建查询、循环遍历结果并逐个删除它们相比）是在两个后续查询中执行此任务：

    paperQuery = db.session.query(Paper.id)\
                                    filter(Paper.journal_id == journal.id)


    baseQuery  = db.session.query(UserPaper)\
                                    .filter(UserPaper.paper_id.in_(paperQuery.subquery()))
                                    .filter(UserPaper.user_id == user.id).delete(synchronize_session='fetch')

它对我来说效果很好，它也应该解决你的问题。

于 2013-12-17T18:19:30.340 回答