3

我正在关注一个教程，我试图让我的文本出现在屏幕上，这是我的代码，但文本不会出现：

from __future__ import division
import math
import sys
import pygame


class MyGame(object):
    def __init__(self):
        pygame.mixer.init()
        pygame.mixer.pre_init(44100, -16, 2, 2048)
        pygame.init()

        self.width = 800
        self.height = 600
        self.screen = pygame.display.set_mode((self.width, self.height))

        self.bg_color = 0, 0, 0

        font = pygame.font.Font(None, 100)

        text = font.render("text that should appear", True, 238, 58, 140)


        self.FPS = 30
        self.REFRESH = pygame.USEREVENT+1
        pygame.time.set_timer(self.REFRESH, 1000//self.FPS)


    def run(self):
        running = True
        while running:
            event = pygame.event.wait()

            if event.type == pygame.QUIT:
                running = False

            elif event.type == self.REFRESH:
                self.draw()

            else:
                pass 

    def draw(self):
        self.screen.fill(self.bg_color)

        screen.blit(text, [400,300])

        pygame.display.flip()


MyGame().run()
pygame.quit()
sys.exit()

知道为什么会这样吗？我忘记导入库还是我的绘图方法有问题？

4

1 回答 1

2

看起来您将colorin 的三个 RGB 值作为三个单独的值传递给render. 它们应该作为单个元组传入。

您还缺少一些selfs. screen.blit(text, [400,300])应该是，如果您希望它在和中都可以访问，则self.screen.blit(text, [400,300])需要将所有实例text变为in 。self.text__init__draw

from __future__ import division
import math
import sys
import pygame


class MyGame(object):
    def __init__(self):
        pygame.mixer.init()
        pygame.mixer.pre_init(44100, -16, 2, 2048)
        pygame.init()

        self.width = 800
        self.height = 600
        self.screen = pygame.display.set_mode((self.width, self.height))

        self.bg_color = 0, 0, 0

        font = pygame.font.Font(None, 100)

        self.text = font.render("text that should appear", True, (238, 58, 140))


        self.FPS = 30
        self.REFRESH = pygame.USEREVENT+1
        pygame.time.set_timer(self.REFRESH, 1000//self.FPS)


    def run(self):
        running = True
        while running:
            event = pygame.event.wait()

            if event.type == pygame.QUIT:
                running = False

            elif event.type == self.REFRESH:
                self.draw()

            else:
                pass 

    def draw(self):
        self.screen.fill(self.bg_color)

        self.screen.blit(self.text, [400,300])

        pygame.display.flip()


MyGame().run()
pygame.quit()
sys.exit()

结果：

在此处输入图像描述

于 2013-11-01T20:20:20.327 回答