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我正在使用 djangorestframework(我喜欢它),我正在尝试将一些数据从前端发布到等待接受它的 REST 视图/序列化器。

当我登录到 REST API 后端(django rest 为用户提供能够测试他们的查询)时,我可以提交此信息,它会成功地将信息传递到后端并保存对象:

{
        "user": 1,
        "content": "this is some content",
        "goal": 
        {
            "competencies[]": [
            32
            ],
            "active": false,
            "completed": false,
            "user": 1
        }
    }

但是,当我运行 POST 请求时,它失败了,说明:

{"goal": ["This field is required."]}

所以这很有趣。它从后端工作,但不是前端。

这是我的附加帮助代码:

//the ajax request 
    $.ajax({
        // obviates need for sameOrigin test
        crossDomain: false, 

        //adds a CSRF header to the request if the method is unsafe (the csrfSafeMethod is in base.html)
        beforeSend: function(xhr, settings) {
            if (!csrfSafeMethod(settings.type)) {
                xhr.setRequestHeader("X-CSRFToken", csrftoken);
            }
        },

        //needed because we're setting data, I think.
        type: "POST",

        //target API url 
        url: '/api/goal-status/add', 

        data: this_instead,

        //on success, reload the page, because everything worked
        success: function(){
            location.reload();                            
alert("In the goal-add click listener");
        },

        //we'll have to find something better to do when an error occurs. I'm still thinking through this. There will probably just have to be some standardized way of going about it. 
        error: function(){
            alert('An error ocurred!'); 
        }
    });

这是响应请求的视图:

class AddGoalStatus(generics.CreateAPIView): 
serializer_class = GoalStatusSerializer
permission_classes = (
    permissions.IsAuthenticated, 
)

以及对应的型号:

class Goal(TimeStampedModel): 
    """A personalized Goal that a user creates to achieve"""
    completed = models.BooleanField(default=False)
    user = models.ForeignKey(User)
    competencies = models.ManyToManyField(CoreCompetency)

    def __unicode__(self):
         return self.user.get_full_name()

class GoalStatus(TimeStampedModel):
    """As goals go on, users will set different statuses towards them"""
    content = models.TextField(max_length=2000)
    goal = models.ForeignKey(Goal, related_name="goal_statuses")

    def __unicode__(self):
        return self.goal.user.get_full_name() + ": " + self.content

    class Meta:
        verbose_name_plural = "Statuses"
    verbose_name = "Goal Status"

这是完整性的序列化程序:

class GoalSerializer(serializers.ModelSerializer): 
    competencies = serializers.PrimaryKeyRelatedField(many=True, read_only=False)
    class Meta: 
        model = Goal

class GoalStatusSerializer(serializers.ModelSerializer):
    goal = GoalSerializer()
    class Meta: 
        model = GoalStatus
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1 回答 1

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正如汤姆克里斯蒂在这里所说:

django rest框架通过POST创建嵌套对象“模型”

Django Rest Framework 不允许您写入嵌套序列化程序。

看起来有工作正在构建这个功能,但我不知道它是否已经完成:

https://github.com/tomchristie/django-rest-framework/tree/writable-nested-modelserializer

同时,请参阅此线程以获取有关如何解决此限制的想法:

https://groups.google.com/forum/#!topic/django-rest-framework/L-TknBDFzTk

于 2013-11-01T18:59:24.690 回答