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我想使用 VBA 以编程方式刷新 Word 模板报告中的 Excel 表格。这些表格被写入 Matlab 模板 Excel 文件中的几张纸上。文件结构将如下所示：在此处输入图像描述

该代码必须检查文件夹结构以查看它是否将 Excel 文件从最新文件夹中拉出。如果是，它只会刷新所有单元格。如果不是，它必须删除所有表并从与之前拉出的表相同的表中插入新表。我不确定下面星号之间的代码。任何帮助将非常感激。

Sub LinkToCurrentTableFolder()
'Get current folder by date
Dim clientTablesPath As Variant
filePath = ActiveDocument.Path & "\ClientTables\"

Set fso = CreateObject("Scripting.FileSystemObject")
Set fld = fso.GetFolder(filePath)
Dim currentFolder As Variant: currentFolder = ""
For Each sf In fld.SUBFOLDERS
    'Look at name and get current date
    If currentFolder = "" Then
        currentFolder = sf.Path
    ElseIf sf.Path > currentFolder Then
        currentFolder = sf.Path
    End If
Next
'***
'Debug: display current Excel folder path
'MsgBox (currentFolder)
If currentPath = currentFolder Then
'Loop through all tables in document and refresh
'If path is not current delete current table
Dim tbTemp As Table
Dim cellTemp As Cell
    For Each tbTemp In ActiveDocument.Tables
    For Each cellTemp In tbTemp.Range.Cells
    cellTemp.Range.Fields.Update
    Next
    Next
Else
'Locate same file name in new folder
shpName = .LinkFormat.SourceName
 NewPath = currentFolder & "\" & shpName
'Delete existing table (???) Not sure
.Delete
'Create new table (???) Not sure - must be from same location and same size as previous one
Selection.Table.AddOLEObject ClassType:=cType, FileName:=NewPath, LinkToFile:=True, DisplayAsIcon:=False
End If
'***
End Sub

编辑 - 复制和粘贴如下所示： 在此处输入图像描述

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1 回答 1

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我在这里找到了答案- 此代码询问新 Excel 文件的位置并更新 Excel 链接表的所有域代码。

该链接的代码如下。

Public Sub changeSource()
Dim dlgSelectFile As FileDialog 'FileDialog object '
Dim thisField As Field
Dim selectedFile As Variant
'must be Variant to contain filepath of selected item
Dim newFile As Variant
Dim fieldCount As Integer '
Dim x As Long
On Error GoTo LinkError
'create FileDialog object as File Picker dialog box
Set dlgSelectFile = Application.FileDialog(FileDialogType:=msoFileDialogFilePicker)
With dlgSelectFile
   .Filters.Clear 'clear filters
  .Filters.Add "Microsoft Excel Files", "*.xls, *.xlsb, *.xlsm, *.xlsx" 'filter for o    nly Excel files
  'use Show method to display File Picker dialog box and return user's action
  If .Show = -1 Then
 'step through each string in the FileDialogSelectedItems collection
    For Each selectedFile In .SelectedItems
         newFile = selectedFile 'gets new filepath
       Next selectedFile
     Else 'user clicked cancel
   Exit Sub
  End If
End With
Set dlgSelectFile = Nothing
'update fields
With ActiveDocument
  fieldCount = .Fields.Count
  For x = 1 To fieldCount
    With .Fields(x)
     'Debug.Print x '
     Debug.Print .Type
      If .Type = 56 Then
        'only update Excel links. Type 56 is an excel link
        .LinkFormat.SourceFullName = newFile '
        .Update
        .LinkFormat.AutoUpdate = False
        DoEvents
      End If
    End With
  Next x
End With
MsgBox "Source data has been successfully imported."
Exit Sub
LinkError:
Select Case Err.Number
  Case 5391 'could not find associated Range Name
    MsgBox "Could not find the associated Excel Range Name " & _
      "for one or more links in this document. " & _
      "Please be sure that you have selected a valid " & _
      "Quote Submission input file.", vbCritical
      Case Else
        MsgBox "Error " & Err.Number & ": " & Err.Description, vbCritical
    End Select
End Sub
于 2013-11-01T20:51:49.733 回答