1

我有一个V:Shape我假设来自 .Doc 文件到 .Docx 文件的转换，但在我编写的代码中，我想要一个DocumentFormat.OpenXml.Drawing.Pictures.Picture.

有没有办法以编程方式转换为Picture?

我正在使用的片段是：

 foreach (var item in value)
 {
   if (!item.Descendants<Picture>().Any()) //pictures are processed differently - they're an absolute s**t storm to code...
   {
     p.Append(item.CloneNode(true));
   }
   else
   {
     p.Append(CreateImageRun(source, item, target, f));
   }
 }

public Run CreateImageRun(WordprocessingDocument sourceDoc, Run sourceRun, WordprocessingDocument target, FooterPart footerPart)
{
  ImagePart newPart = footerPart.AddImagePart(ImagePartType.Png);

  ImageData shape = sourceRun.Descendants<ImageData>().FirstOrDefault();

  ImagePart p = sourceDoc.MainDocumentPart.GetPartById(shape.RelationshipId) as ImagePart;

  Bitmap image = new Bitmap(p.GetStream()); 

  using (Stream s = p.GetStream())
  {
    s.Position = 0;
    newPart.FeedData(s);
  }

  string partId = footerPart.GetIdOfPart(newPart);

  Drawing newImage = CreateImage(partId);

  return new Run(newImage);
}

private Drawing CreateImage(string relationshipId)
{
  // Define the reference of the image.
  return new Drawing(
                     new DW.Inline(
                         new DW.Extent() { Cx = 990000L, Cy = 792000L },
                         new DW.EffectExtent()
                         {
                             LeftEdge = 0L,
                             TopEdge = 0L,
                             RightEdge = 0L,
                             BottomEdge = 0L
                         },
                         new DW.DocProperties()
                         {
                             Id = (UInt32Value)1U,
                             Name = "Picture 1"
                         },
                         new DW.NonVisualGraphicFrameDrawingProperties(
                             new A.GraphicFrameLocks() { NoChangeAspect = true }),
                         new A.Graphic(
                             new A.GraphicData(
                                 new PIC.Picture(
                                     new PIC.NonVisualPictureProperties(
                                         new PIC.NonVisualDrawingProperties()
                                         {
                                             Id = (UInt32Value)0U,
                                             Name = "New Bitmap Image.jpg"
                                         },
                                         new PIC.NonVisualPictureDrawingProperties()),
                                     new PIC.BlipFill(
                                         new A.Blip(
                                             new A.BlipExtensionList(
                                                 new A.BlipExtension()
                                                 {
                                                     Uri =
                                                       "{28A0092B-C50C-407E-A947-70E740481C1C}"
                                                 })
                                         )
                                         {
                                             Embed = relationshipId,
                                             CompressionState =
                                             A.BlipCompressionValues.Print
                                         },
                                         new A.Stretch(
                                             new A.FillRectangle())),
                                     new PIC.ShapeProperties(
                                         new A.Transform2D(
                                             new A.Offset() { X = 0L, Y = 0L },
                                             new A.Extents() { Cx = 990000L, Cy = 792000L }),
                                         new A.PresetGeometry(
                                             new A.AdjustValueList()
                                         ) { Preset = A.ShapeTypeValues.Rectangle }))
                             ) { Uri = "http://schemas.openxmlformats.org/drawingml/2006/picture" })
                     )
                     {
                         DistanceFromTop = (UInt32Value)0U,
                         DistanceFromBottom = (UInt32Value)0U,
                         DistanceFromLeft = (UInt32Value)0U,
                         DistanceFromRight = (UInt32Value)0U,
                         EditId = "50D07946"
                     });
        }

完整的代码上下文在这里是另一个问题：

创建 ImagePart 不会在 OpenXML 中保存关系

4

1 回答 1

2

我找到了一种快速/简单的方法来做到这一点——我应该早点解决！

该Shape对象有一个ImageData对象作为后代，所以我检查了它，并通过一个额外的方法运行它来获取ImagePart：

A.Blip pic = item.Descendants<A.Blip>().FirstOrDefault();

ImageData imageData = item.Descendants<ImageData>().FirstOrDefault();

if (pic == null && imageData == null) //pictures are processed differently - they're an absolute s**t storm to code...
{
  runToAmend.InsertAfterSelf(item.CloneNode(true));
}
else
{
  if(pic != null)
  {
    runToAmend.InsertAfterSelf(CreateImageFromBlip(source, item, footerHeaderPart,pic));
  }
  else if (imageData != null)
  {
    runToAmend.InsertAfterSelf(CreateImageFromShape(source, item, footerHeaderPart, imageData));
  }
}

然后创建了一个新方法——CreateImageFromShape(..)然后调用原来的 CreateImageRun。

private Run CreateImageFromShape(WordprocessingDocument sourceDoc, Run sourceRun, OpenXmlPart headerFooterPart, ImageData imageData)
{
  ImagePart p = sourceDoc.MainDocumentPart.GetPartById(imageData.RelationshipId) as ImagePart;

  return CreateImageRun(sourceDoc, sourceRun, headerFooterPart, p);
}

任务完成。

于 2013-11-01T11:42:36.703 回答