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  1. 如何从“发布”网络服务获得以下响应。

  2. 我有一个名为 textArray 的字符串数组。如何在以下响应中为键 @"Answer" 发布该 textArray。

          {
        "ProjID": "78",
        "Uid": "12",
        "EmailID": "ratnam_nv@yahoo.com",
        "ProjectInviterFQAnswers": [{
            "slno": "1",
            "Answer": "a1",
            "order": "1",
            "flag": "F"
        }, {
            "slno": "2",
            "Answer": "a1",
            "order": "2",
            "flag": "F"
        }, {
            "slno": "1",
            "Answer": "a1",
            "order": "2",
            "flag": "Q"
        }
        ]
    };

这是我到目前为止尝试过的

NSError *error = Nil;
    NSOperationQueue *queue = [[NSOperationQueue alloc] init];


NSDictionary *dictionaryArray1 = [NSDictionary dictionaryWithObjectsAndKeys:@"1", @"slno", @"a1", @"Answer", @"1", @"order", @"F", @"Flag", nil];

NSDictionary *dictionaryArray2 = [NSDictionary dictionaryWithObjectsAndKeys:@"2", @"slno", @"a1", @"Answer", @"1", @"order", @"F", @"Flag", nil];

NSDictionary *dictionaryArray3 = [NSDictionary dictionaryWithObjectsAndKeys:@"1", @"slno", @"a1", @"Answer", @"2", @"order", @"Q", @"Flag", nil];

NSArray *arrayAnswer = [NSArray arrayWithObjects:dictionaryArray1, dictionaryArray2, dictionaryArray3, nil];

NSDictionary *dictionary = [NSDictionary dictionaryWithObjectsAndKeys:@"78", @"ProjID", @"12", @"UID", @"ratnam_nv@yahoo.com", @"EmailID", arrayAnswer, @"ProjectInviterFQAnswer", nil];

    NSURL *url = [NSURL URLWithString:@" someurl "];
    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url];
    NSData *requestData = [NSJSONSerialization dataWithJSONObject:dictionary options:kNilOptions error:&error];
    [request setHTTPMethod:@"POST"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
    [request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
    [request setHTTPBody: requestData];
    NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
    [connection start];
    [NSURLConnection sendAsynchronousRequest:request queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error){
        if(error || !data)
        {
            NSLog(@"JSON Data not posted!");
            [activity stopAnimating];
            UIAlertView *alertMessage = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Data not saved" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
            [alertMessage show];
        }
        else
        {
            [activity startAnimating];
            NSLog(@"JSON data posted! :)");
            NSError *error = Nil;
            NSJSONSerialization *jsonObject = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&error];
            NSLog(@"Response is %@", jsonObject); //Not getting the response here Message = "An error has occurred."
            [activity stopAnimating];
        }

    }];
4

2 回答 2

1

请注意：

NSArray *keys = [NSArray arrayWithObjects:@"slno", @"Answer", @"order", @"flage", nil];

但是你有：

"flag": "Q"

标志！=标志。

这就是为什么最好使用常量！

接下来，关于你的问题：

首先，您必须将 JSON 转换为 NSDictionary。

后：

NSArray * array = [jsonDict valueForKey:@"ProjectInviterFQAnswer"];
for(NSMutableDictionary * dict in array){
     [dict setValue:<put here anything you want> forKey:@""];
}

在你这样做之后，从 jsonDict 创建一个新的 JSON，你就完成了。

于 2013-10-31T12:38:23.530 回答
0

首先，您必须将响应转换为字典并设置回答您的 textArray 字符串的值，然后再次将其转换为 json 字符串

于 2013-10-31T12:35:35.493 回答