4

我有一个搜索表单，我想放置一个分页，但是当我使用 pagination 在搜索中按下下一个按钮或第二页时，所有结果都搞砸了，并且没有从查询中获取数据。我不知道确切的问题可能出在哪里，但这是我的搜索代码：

include ('paginate.php'); //include of paginat page

$per_page = 5;   
$find = $_POST['find'];
$find = strtoupper($find); 
$find = strip_tags($find); 
$find = trim ($find);       // number of results to show per page
$result = mysql_query("SELECT * FROM projects WHERE p_name LIKE '%$find%'");
$total_results = mysql_num_rows($result);
$total_pages = ceil($total_results / $per_page);//total pages we going to have

//------------if page is setcheck-----------------//
if (isset($_GET['page'])) {
    $show_page = $_GET['page'];             //it will telles the current page
    if ($show_page > 0 && $show_page <= $total_pages) {
        $start = ($show_page - 1) * $per_page;
        $end = $start + $per_page;
    } else {
        // error - show first set of results
        $start = 1;              
        $end = $per_page;
    }
} else {
    // if page isn't set, show first set of results
    $start = 0;
    $end = $per_page;
    $show_page=1;
}
// display pagination
if(isset($_GET['page'])){
    $page = intval($_GET['page']);
}else{
     $page =1;
}


$tpages=$total_pages;
if ($page <= 0)
    $page = 1;
?>
 <?php
                    $reload = $_SERVER['PHP_SELF'] . "?tpages=" . $tpages;
                    echo '<div class="pagination"><ul>';
                    if ($total_pages > 1) {
                        echo paginate($reload, $show_page, $total_pages);
                    }
                    echo "</ul></div>";
                    // display data in table
                    echo "<table class='table table-bordered'>";
                    echo "<thead><tr><th>Project</th> <th>Country</th> <th>Active</th>
                </tr></thead>";
                     for ($i = $start; $i < $end; $i++) {
                        // make sure that PHP doesn't try to show results that don't exist
                        if ($i == $total_results) {
                            break;
                        }
                     ?><form name="frmactive" method="POST" action=""> 
                     <input type="hidden" name="id" value="<?php echo mysql_result($result, $i, 'p_id');?>" />
                       <?php
                        // echo out the contents of each row into a table
                        echo '<tr><td>' . mysql_result($result, $i, 'p_name') . '</td>';
                        echo '<td>' . mysql_result($result, $i, 'p_country') . '</td>';
                        if (mysql_result($result, $i, 'p_isActive')=='1'){ 
                        echo '<td>Active</td>';
                         echo '<td align="center"><a href="activeproject.php?id=' . mysql_result($result, $i, 'p_id') . '">Edit</a></td>';
 }
 else{
    echo'<td>Inactive</td> ';
    echo '<td  align="center"><a href="activeproject.php?id=' . mysql_result($result, $i, 'p_id') . '">Edit</a></td>';
                        echo "</tr>";
                    }       
                    // close table>
                     }
                echo "</table>";
            // pagination
            ?>

这是 paginate.php

function paginate($reload, $page, $tpages) {
    $adjacents = 2;
    $prevlabel = "&lsaquo; Prev";
    $nextlabel = "Next &rsaquo;";
    $out = "";
    // previous
    if ($page == 1) { 
        $out.= "<span>" . $prevlabel . "</span>\n";
    } elseif ($page == 2) {
        $out.= "<li><a  href=\"" . $reload . "\">" . $prevlabel . "</a>\n</li>";
    } else {
        $out.= "<li><a  href=\"" . $reload . "&amp;page=" . ($page - 1) . "\">" . $prevlabel . "</a>\n</li>";
    }

    $pmin = ($page > $adjacents) ? ($page - $adjacents) : 1;
    $pmax = ($page < ($tpages - $adjacents)) ? ($page + $adjacents) : $tpages;
    for ($i = $pmin; $i <= $pmax; $i++) {
        if ($i == $page) {
            $out.= "<li  class=\"active\"><a href=''>" . $i . "</a></li>\n";
        } elseif ($i == 1) {
            $out.= "<li><a  href=\"" . $reload . "\">" . $i . "</a>\n</li>";
        } else {
            $out.= "<li><a  href=\"" . $reload . "&amp;page=" . $i . "\">" . $i . "</a>\n</li>";
        }
    }

    if ($page < ($tpages - $adjacents)) {
        $out.= "<a style='font-size:11px' href=\"" . $reload . "&amp;page=" . $tpages . "\">" . $tpages . "</a>\n";
    }
    // next
    if ($page < $tpages) {
        $out.= "<li><a  href=\"" . $reload . "&amp;page=" . ($page + 1) . "\">" . $nextlabel . "</a>\n</li>";
    } else {
        $out.= "<span style='font-size:11px'>" . $nextlabel . "</span>\n";
    }
    $out.= "";
    return $out;
}

你能指出错误发生在哪里吗？感谢您的时间

4

1 回答 1

0

试试这个（请注意评论）：

<?php
 /*
 Assuming that your search form has a POST method set to it,
 be sure to do a redirect to this page and send the find parameter gotten
 from the posted form urlencoded

 ie path_to_my_file?find='.urlencode(trim($_POST['find']))
 */
 include ('paginate.php'); //include of paginat page

 $per_page = 5;   
 $find = strip_tags(strtoupper(trim(urldecode($_GET['find']))));
 $page = intval($_GET['page']);

 $result_total = mysql_query("SELECT COUNT(*) AS total FROM projects WHERE p_name LIKE '%".$find."%'");
 $tmp_total = mysql_fetch_assoc($results_total);

 $totalpages = ceil($tmp_total['total'] / $per_page);

 if ($totalpages != 0 && $page > $totalpages) {
      $page = $totalpages;
 } else if ($page < 1) {
      $page = 1;
 }

 $offset = ($page - 1) * $per_page;

 $result = mysql_query("SELECT * FROM projects WHERE p_name LIKE '%".$find."%' LIMIT ".$offset.", ".$per_page);

 $show_page = 1;
 //You need to pass the phrase you are searching for in every link in order for the pagination to work (or user Sessions to save the keyword somewhere if you don't want it in the link)
 $reload = $reload = 'http://localhost/Personal/Stackoverflow/2/index.php?find='.urlencode($find);

 echo '    <div class="pagination">
           <ul>';

 if ($totalpages > 1) {
     echo paginate($reload, $show_page, $totalpages);
 }

 echo '    </ul>
           </div>';

 // display data in table
 if(mysql_num_rows($result) > 0) {
      echo '    <table class="table table-bordered">
                <thead>
                <tr>
                     <th>Project</th>
                     <th>Country</th>
                     <th>Active</th>
                </tr>
                </thead>';

      while($row = mysql_fetch_assoc($result)) { 
           echo '    <tr>
                          <td>'.$row['p_name'].'</td>
                          <td>'.$row['p_country'].'</td>
                          <td>'.((intval($row['p_isActive']) == 1) ? 'Active' : 'Inactive').'</td>
                          <td align="center">
                               <a href="activeproject.php?id='.$row['p_id'].'">Edit</a>
                          </td>
                     </tr>';
      }

      echo '    </table>';
 }
?>
于 2014-05-03T04:44:33.003 回答