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我有一个小型 Django 应用程序，当我使用 django orm 查询我的数据库时，我得到了我的对象列表。我想要的是查询匹配的 db 列的名称。有可能吗？

提前致谢！

results = Verbs.objects.filter(
        Q(fps__icontains = " " + word_name + " ") | Q(fps__endswith = " " + word_name) | Q(fps__startswith = word_name + " ") |
        Q(sps__icontains = " " + word_name + " ") | Q(sps__endswith = " " + word_name) | Q(sps__startswith = word_name + " ") |
        Q(tps__icontains = " " + word_name + " ") | Q(tps__endswith = " " + word_name) | Q(tps__startswith = word_name + " ") |
        Q(fpp__icontains = " " + word_name + " ") | Q(fpp__endswith = " " + word_name) | Q(fpp__startswith = word_name + " ") |
        Q(spp__icontains = " " + word_name + " ") | Q(spp__endswith = " " + word_name) | Q(spp__startswith = word_name + " ") |
        Q(tpp__icontains = " " + word_name + " ") | Q(tpp__endswith = " " + word_name) | Q(tpp__startswith = word_name + " ")
        ).all()

我想要的是查询匹配的字段名称。例如：fps 或 fpp ...

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1 回答 1

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我认为这就是您想要的-对于每个返回的行，它将打印匹配的字段，缩进：

fields = ('fps', 'sps', 'tps', 'fpp', 'spp', 'tpp')
for r in results.values():
    print 'Row with id=%s:' % r['id']
    for f in fields:
        if word_name in str(r[f]):
            print '  Field %s matches' % f

编辑以考虑非字符串值并仅查看所需字段。

于 2013-10-30T15:46:29.197 回答