我正在检查类 org.apache.http.auth。如果有人有,还有更多参考或示例吗?
问问题
124826 次
6 回答
118
对我来说,它奏效了,
final String basicAuth = "Basic " + Base64.encodeToString("user:password".getBytes(), Base64.NO_WRAP);
Apache HttpCLient:
request.setHeader("Authorization", basicAuth);
HttpUrl连接:
connection.setRequestProperty ("Authorization", basicAuth);
于 2012-02-21T12:24:11.517 回答
80
我以前没有遇到过那个特定的包,但它说它是用于客户端 HTTP 身份验证的,我已经能够使用java.net
API 在 Android 上执行此操作,如下所示:
Authenticator.setDefault(new Authenticator(){
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication("myuser","mypass".toCharArray());
}});
HttpURLConnection c = (HttpURLConnection) new URL(url).openConnection();
c.setUseCaches(false);
c.connect();
显然,您的 getPasswordAuthentication() 可能应该做一些比返回常量更智能的事情。
如果您尝试使用POST
带有身份验证的正文(例如)发出请求,请注意Android 问题 4326。我已经将建议的修复链接到那里的平台,但是如果您只想要基本身份验证,有一个简单的解决方法:不要打扰 Authenticator,而是这样做:
c.setRequestProperty("Authorization", "basic " +
Base64.encode("myuser:mypass".getBytes(), Base64.NO_WRAP));
于 2009-12-28T10:39:01.783 回答
14
您可以手动插入 http 标头来请求:
HttpGet request = new HttpGet(...);
request.setHeader("Authorization", "Basic "+Base64.encodeBytes("login:password".getBytes()));
于 2011-03-15T19:24:28.583 回答
13
手动方法适用于 import android.util.Base64,但请务必在调用编码时设置 Base64.NO_WRAP:
String basicAuth = "Basic " + new String(Base64.encode("user:pass".getBytes(),Base64.NO_WRAP ));
connection.setRequestProperty ("Authorization", basicAuth);
于 2012-01-08T17:37:32.593 回答
3
于 2010-06-04T11:34:12.943 回答
1
这对我有用
URL imageUrl = new URL(url);
HttpURLConnection conn = (HttpURLConnection) imageUrl
.openConnection();
conn.setRequestProperty("Authorization", "basic " +
Base64.encode("username:password".getBytes()));
conn.setConnectTimeout(30000);
conn.setReadTimeout(30000);
conn.setInstanceFollowRedirects(true);
InputStream is = conn.getInputStream();
于 2014-06-24T07:46:23.437 回答