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谁能告诉我一个例子来更新和删除一对一休眠映射中的记录？

我有 2 个表客户和客户地址。我可以使用以下代码在两个表中添加记录

customerForm.setcustomerAddress(customerAddress);
customerAddress.setCustomer(customerForm);
getEntityManager().persist(customerForm);

现在我想删除和更新记录。

@Entity
@Table(name="customers")
public class Customer {
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name="id")
public int getId() {
    return id;
}
@Column(name="customerName")
public String getcustomerName() {
    return customerName;
}
@Column(name="password")
public String getpassword() {
    return password;
}


@OneToOne(mappedBy = "customer", cascade = CascadeType.ALL)  
public CustomerAddess getcustomerAddress() {
    return customerAddress;
}
//rest setter getter.....

}

@Entity
@Table(name="customer_address")
public class CustomerAddess {
@Id
@GeneratedValue(generator = "gen")  
@GenericGenerator(name = "gen", strategy = "foreign", parameters =    @org.hibernate.annotations.Parameter(name = "property", value = "customer"))  
@Column(name="id")
public int getId() {
    return id;
}

@Column(name="street_address")
public String getstreet_address() {
    return street_address;
}
@OneToOne(fetch = FetchType.EAGER)
@PrimaryKeyJoinColumn  
public Customer getCustomer() {
    return customer;
}

//rest setter getter
4

1 回答 1

0

我举了你的例子并创建了两个简单的测试套件，它们应该为你提供有关如何持久化/更新/删除实体的概述。

我还稍微修改了您的实体（如果注释在 getter/setter 之上，我不喜欢它，所以我将它们放在字段之上，并为 getter/setter 应用了 javabeans 约定，并删除了一些拼写错误）。有一些评论也可能会给你一些提示。

CascadeAllTests：

@OneToOne(mappedBy = "customer", cascade = CascadeType.ALL)
    CustomerAddress customerAddress;



public class CascadeAllTests {
    private EntityManager em;

    @Before
    public void before() {
        final EntityManagerFactory emf = Persistence
                .createEntityManagerFactory("pu");
        em = emf.createEntityManager();
    }

    @After
    public void after() {
        em.close();
        em = null;
    }

    @Test
    public void persist() {
        Customer c = new Customer();
        c.setCustomerName("cName");
        c.setPassword("cPass");
        CustomerAddress addr = new CustomerAddress();
        addr.setCustomer(c);
        addr.setStreetAddress("Addr");
        c.setCustomerAddress(addr);

        em.getTransaction().begin();
        em.persist(c); // it is not necessary to call em.persist(addr)
        em.getTransaction().commit();

        Customer cStored = em.find(Customer.class, c.getId());
        assertNotNull(cStored);
        assertEquals(c.getCustomerName(), cStored.getCustomerName());
        assertEquals(addr.getStreetAddress(), cStored.getCustomerAddress()
                .getStreetAddress());
    }

    @Test
    public void update() {
        Customer c = new Customer();
        c.setCustomerName("cName");
        c.setPassword("cPass");
        CustomerAddress addr = new CustomerAddress();
        addr.setCustomer(c);
        addr.setStreetAddress("Addr");
        c.setCustomerAddress(addr);

        em.getTransaction().begin();
        em.persist(c);
        em.getTransaction().commit();

        em.detach(c); // c and c.customerAddress are detached now.

        addr.setStreetAddress("New address");
        c.setCustomerName("New Name");
        em.getTransaction().begin();
        c = em.merge(c);
        em.getTransaction().commit();
        // due to CascadeType.ALL on Customer.customerAddress the new address is
        // stored now

        Customer cStored = em.find(Customer.class, c.getId());
        assertNotNull(cStored);
        assertEquals(c.getCustomerName(), cStored.getCustomerName());
        assertEquals(addr.getStreetAddress(), cStored.getCustomerAddress()
                .getStreetAddress());
    }

    @Test
    public void deleteAddressOnly() {
        Customer c = new Customer();
        c.setCustomerName("cName");
        c.setPassword("cPass");
        CustomerAddress addr = new CustomerAddress();
        addr.setCustomer(c);
        addr.setStreetAddress("Addr");
        c.setCustomerAddress(addr);

        em.getTransaction().begin();
        em.persist(c);
        em.getTransaction().commit();

        em.detach(c); // c and c.customerAddress are detached now

        em.getTransaction().begin();
        c = em.merge(c); // c and c.customerAddress are attached again
        em.remove(c.getCustomerAddress());
        c.setCustomerAddress(null);
        em.getTransaction().commit();
        // due to CascadeType.ALL on Customer.customerAddress the new address is
        // stored now

        Customer cStored = em.find(Customer.class, c.getId());
        CustomerAddress addrStored = em.find(CustomerAddress.class,
                addr.getId());
        assertNotNull(cStored);
        assertEquals(c.getCustomerName(), cStored.getCustomerName());
        assertNull(cStored.getCustomerAddress());
        assertNull(addrStored);
    }
}

CascadeNoneTests：

@OneToOne(mappedBy = "customer", cascade = {})
    CustomerAddress customerAddress;

public class CascadeNonTests {
    private EntityManager em;

    @Before
    public void before() {
        final EntityManagerFactory emf = Persistence
                .createEntityManagerFactory("pu");
        em = emf.createEntityManager();
    }

    @After
    public void after() {
        em.close();
        em = null;
    }

    @Test
    public void persist() {
        Customer c = new Customer();
        c.setCustomerName("cName");
        c.setPassword("cPass");
        CustomerAddress addr = new CustomerAddress();
        addr.setCustomer(c);
        addr.setStreetAddress("Addr");
        c.setCustomerAddress(addr);

        em.getTransaction().begin();
        em.persist(c);
        em.persist(addr); // has to be called explicitly
        em.getTransaction().commit();

        Customer cStored = em.find(Customer.class, c.getId());
        assertNotNull(cStored);
        assertEquals(c.getCustomerName(), cStored.getCustomerName());
        assertEquals(addr.getStreetAddress(), cStored.getCustomerAddress()
                .getStreetAddress());
    }

    @Test
    public void update() {
        Customer c = new Customer();
        c.setCustomerName("cName");
        c.setPassword("cPass");
        CustomerAddress addr = new CustomerAddress();
        addr.setCustomer(c);
        addr.setStreetAddress("Addr");
        c.setCustomerAddress(addr);

        em.getTransaction().begin();
        em.persist(c);
        em.persist(addr);// has to be called explicitly
        em.getTransaction().commit();

        em.detach(c);
        em.detach(addr); // c and c.customerAddress are detached now.

        addr.setStreetAddress("New address");
        c.setCustomerName("New Name");
        em.getTransaction().begin();
        c = em.merge(c);
        addr = em.merge(addr);
        em.getTransaction().commit();

        Customer cStored = em.find(Customer.class, c.getId());
        assertNotNull(cStored);
        assertEquals(c.getCustomerName(), cStored.getCustomerName());
        assertEquals(addr.getStreetAddress(), cStored.getCustomerAddress()
                .getStreetAddress());
    }

    @Test
    public void deleteAddressOnly() {
        Customer c = new Customer();
        c.setCustomerName("cName");
        c.setPassword("cPass");
        CustomerAddress addr = new CustomerAddress();
        addr.setCustomer(c);
        addr.setStreetAddress("Addr");
        c.setCustomerAddress(addr);

        em.getTransaction().begin();
        em.persist(c);
        em.persist(addr);// has to be called explicitly
        em.getTransaction().commit();

        em.detach(c);
        em.detach(addr); // c and c.customerAddress are detached now.

        em.getTransaction().begin();
        c = em.merge(c);
        addr = em.merge(addr);
        em.remove(c.getCustomerAddress());
        c.setCustomerAddress(null);
        em.getTransaction().commit();

        Customer cStored = em.find(Customer.class, c.getId());
        CustomerAddress addrStored = em.find(CustomerAddress.class,
                addr.getId());
        assertNotNull(cStored);
        assertEquals(c.getCustomerName(), cStored.getCustomerName());
        assertNull(cStored.getCustomerAddress());
        assertNull(addrStored);
    }
}
于 2013-10-31T11:06:56.683 回答