我NSRegularExpression用来解压一个字符串。将@"A" 转为@",-1" 并将@"B" 转为@",-2" 以解压。
问题是如果只@"A" to @",-1" or @"B" to @",-2"单独应用，它工作正常。但是当在 for 循环中同时应用时，我发现enumerateMatchesInString:options:range:usingBlock在 search 时找不到匹配项@"B"。有任何想法吗？
NSString *compressed = @"[303b18c01a,Ac24a6,Aa6,,Ah,A,a1,,,a8,b,c5,aad,bcg,dha9,fa4a7,ib4a9,da4a5,ca1a6,aha7,aea6,,aa6,BCa8,]";
NSMutableString *compressedCopy = [compressed mutableCopy];
//the array contains two patterns
NSArray *regulars = @[[self regexO:@"A" n:@",-1"],
[self regexO:@"B" n:@",-2"]];
NSInteger count = [regulars count];
for (int i = 0; i < count; i++) {
NSDictionary *regexInfo = regulars[i];
NSString *old = regexInfo[REGEX_OLD_KEY];
NSString *new = regexInfo[REGEX_NEW_KEY];
NSString *origin = [compressedCopy copy];
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:old options:0 error:nil];
if (regex) {
__block int offset = 0;
[regex enumerateMatchesInString:origin options:0 range:NSMakeRange(0, [compressed length]) usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {
NSRange range = [result range];
range.location += offset;
[compressedCopy replaceCharactersInRange:range withString:new];
offset += [new length] - [old length];
}];
}
接下来是保存模式
- (NSDictionary *)regexO:(NSString *)old n:(NSString *)new
{
NSDictionary *regex = @{REGEX_OLD_KEY: old, REGEX_NEW_KEY: new};
return regex;
}
--------------------------为了更清楚-------- ------
原始数据是包含许多点坐标的数组，例如：
[131,61,648,1,1,-1,0]
我需要处理的压缩数据就像-> NSString *compressed。
解压的算法是改变压缩字符串中的字符，比如把“A”改成@“,-1”。