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我NSRegularExpression用来解压一个字符串。将@"A" 转为@",-1" 并将@"B" 转为@",-2" 以解压。

问题是如果只@"A" to @",-1" or @"B" to @",-2"单独应用，它工作正常。但是当在 for 循环中同时应用时，我发现enumerateMatchesInString:options:range:usingBlock在 search 时找不到匹配项@"B"。有任何想法吗？

NSString *compressed = @"[303b18c01a,Ac24a6,Aa6,,Ah,A,a1,,,a8,b,c5,aad,bcg,dha9,fa4a7,ib4a9,da4a5,ca1a6,aha7,aea6,,aa6,BCa8,]";
NSMutableString *compressedCopy = [compressed mutableCopy];

//the array contains two patterns
NSArray *regulars = @[[self regexO:@"A" n:@",-1"],
                      [self regexO:@"B" n:@",-2"]];

NSInteger count = [regulars count];
    for (int i = 0; i < count; i++) {

        NSDictionary *regexInfo = regulars[i];
        NSString *old = regexInfo[REGEX_OLD_KEY];
        NSString *new = regexInfo[REGEX_NEW_KEY];

        NSString *origin = [compressedCopy copy];

        NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:old options:0 error:nil];

        if (regex) {
            __block int offset = 0;
            [regex enumerateMatchesInString:origin options:0 range:NSMakeRange(0, [compressed length]) usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {

                NSRange range = [result range];
                range.location += offset;
                [compressedCopy replaceCharactersInRange:range withString:new];
                offset += [new length] - [old length];
            }];
    }

接下来是保存模式

- (NSDictionary *)regexO:(NSString *)old n:(NSString *)new
{
    NSDictionary *regex = @{REGEX_OLD_KEY: old, REGEX_NEW_KEY: new};
    return regex;
}

--------------------------为了更清楚-------- ------

原始数据是包含许多点坐标的数组，例如：

[131,61,648,1,1,-1,0]

我需要处理的压缩数据就像-> NSString *compressed。

解压的算法是改变压缩字符串中的字符，比如把“A”改成@“,-1”。

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1 回答 1

0

终于发现这是一个愚蠢的错误。传递给该方法的范围是错误的，因此它无法生成正确的结果。

[regex enumerateMatchesInString:origin options:0 range:NSMakeRange(0, [origin length]) usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop)
于 2013-10-31T02:45:57.737 回答