有没有办法通过单击列对Tk Treeview 中的条目进行排序?令人惊讶的是,我找不到任何文档/教程。
问问题
20966 次
6 回答
27
patthoyts from#tcl
指出 TreeView Tk 演示程序具有排序功能。这是它的 Python 等价物:
def treeview_sort_column(tv, col, reverse):
l = [(tv.set(k, col), k) for k in tv.get_children('')]
l.sort(reverse=reverse)
# rearrange items in sorted positions
for index, (val, k) in enumerate(l):
tv.move(k, '', index)
# reverse sort next time
tv.heading(col, command=lambda: \
treeview_sort_column(tv, col, not reverse))
[...]
columns = ('name', 'age')
treeview = ttk.TreeView(root, columns=columns, show='headings')
for col in columns:
treeview.heading(col, text=col, command=lambda: \
treeview_sort_column(treeview, col, False))
[...]
于 2009-12-28T02:49:20.750 回答
22
这在 python3 中不起作用。由于变量是通过引用传递的,所有的 lambdas 最终都引用了列中相同的最后一个元素。
这对我有用:
for col in columns:
treeview.heading(col, text=col, command=lambda _col=col: \
treeview_sort_column(treeview, _col, False))
于 2015-06-09T06:53:10.530 回答
4
madonius是对的,但在这里你有完整的例子和一个适当的、可以理解的解释
Sridhar Ratnakumar提供的答案在 python3 中不起作用(显然在 python2.7 中):由于变量是通过引用传递的,所有 lambdas 最终都会引用列中相同的最后一个元素。
你只需要改变这个for loop
:
for col in columns:
treeview.heading(col, text=col, command=lambda _col=col: \
treeview_sort_column(treeview, _col, False))
并且必须将相同的更改应用于 treeview_sort_column 中的 lambda 函数
所以完整的解决方案如下所示:
def treeview_sort_column(tv, col, reverse):
l = [(tv.set(k, col), k) for k in tv.get_children('')]
l.sort(reverse=reverse)
# rearrange items in sorted positions
for index, (val, k) in enumerate(l):
tv.move(k, '', index)
# reverse sort next time
tv.heading(col, text=col, command=lambda _col=col: \
treeview_sort_column(tv, _col, not reverse))
[...]
columns = ('name', 'age')
treeview = ttk.TreeView(root, columns=columns, show='headings')
for col in columns:
treeview.heading(col, text=col, command=lambda _col=col: \
treeview_sort_column(treeview, _col, False))
[...]
于 2020-04-29T06:08:21.790 回答
3
我在尝试为 DB 创建视图时遇到了同样的问题,
受Sridhar Ratnakumar Answer 的启发,
我宁愿采用与他相同的原则并升级 Treeview 类。
class MyTreeview(ttk.Treeview):
def heading(self, column, sort_by=None, **kwargs):
if sort_by and not hasattr(kwargs, 'command'):
func = getattr(self, f"_sort_by_{sort_by}", None)
if func:
kwargs['command'] = partial(func, column, False)
return super().heading(column, **kwargs)
def _sort(self, column, reverse, data_type, callback):
l = [(self.set(k, column), k) for k in self.get_children('')]
l.sort(key=lambda t: data_type(t[0]), reverse=reverse)
for index, (_, k) in enumerate(l):
self.move(k, '', index)
self.heading(column, command=partial(callback, column, not reverse))
def _sort_by_num(self, column, reverse):
self._sort(column, reverse, int, self._sort_by_num)
def _sort_by_name(self, column, reverse):
self._sort(column, reverse, str, self._sort_by_name)
def _sort_by_date(self, column, reverse):
def _str_to_datetime(string):
return datetime.strptime(string, "%Y-%m-%d %H:%M:%S")
self._sort(column, reverse, _str_to_datetime, self._sort_by_date)
...
# Some code
...
treeview.heading('number', text='number', sort_by='num')
treeview.heading('name', text='name', sort_by='name')
treeview.heading('date', text='date', sort_by='date')
只是把这个放在这里:)
于 2020-08-16T01:14:41.200 回答
1
如果表中有整数,则对函数进行这个小改动,它看起来像这样。
def treeview_sort_column(treeview: ttk.Treeview, col, reverse: bool):
"""
to sort the table by column when clicking in column
"""
try:
data_list = [
(int(treeview.set(k, col)), k) for k in treeview.get_children("")
]
except Exception:
data_list = [(treeview.set(k, col), k) for k in treeview.get_children("")]
data_list.sort(reverse=reverse)
# rearrange items in sorted positions
for index, (val, k) in enumerate(data_list):
treeview.move(k, "", index)
# reverse sort next time
treeview.heading(
column=col,
text=col,
command=lambda _col=col: treeview_sort_column(
treeview, _col, not reverse
),
)
于 2020-08-19T16:51:45.910 回答
0
这是对包含字符串、数字、带有千位分隔符的数字、带有多个十进制值的代码的列进行排序的工作代码。
import tkinter as objTK
from tkinter import ttk as objTTK
from functools import partial
import datetime as objDateTime
class MyTreeview(objTTK.Treeview):
def heading(self, column, sort_by=None, **kwargs):
if sort_by and not hasattr(kwargs, 'command'):
func = getattr(self, f"_sort_by_{sort_by}", None)
if func:
kwargs['command'] = partial(func, column, False)
# End of if
# End of if
return super().heading(column, **kwargs)
# End of heading()
def _sort(self, column, reverse, data_type, callback):
l = [(self.set(k, column), k) for k in self.get_children('')]
l.sort(key=lambda t: data_type(t[0]), reverse=reverse)
for index, (_, k) in enumerate(l):
self.move(k, '', index)
# End of for loop
self.heading(column, command=partial(callback, column, not reverse))
# End of _sort()
def _sort_by_num(self, column, reverse):
self._sort(column, reverse, int, self._sort_by_num)
# End of _sort_by_num()
def _sort_by_name(self, column, reverse):
self._sort(column, reverse, str, self._sort_by_name)
# End of _sort_by_num()
def _sort_by_date(self, column, reverse):
def _str_to_datetime(string):
return objDateTime.datetime.strptime(string, "%Y-%m-%d")
# End of _str_to_datetime()
self._sort(column, reverse, _str_to_datetime, self._sort_by_date)
# End of _sort_by_num()
def _sort_by_multidecimal(self, column, reverse):
def _multidecimal_to_str(string):
arrString = string.split(".")
strNum = ""
for iValue in arrString:
strValue = f"{int(iValue):02}"
strNum = "".join([strNum, str(strValue)])
# End of for loop
strNum = "".join([strNum, "0000000"])
return int(strNum[:8])
# End of _multidecimal_to_str()
self._sort(column, reverse, _multidecimal_to_str, self._sort_by_multidecimal)
# End of _sort_by_num()
def _sort_by_numcomma(self, column, reverse):
def _numcomma_to_num(string):
return int(string.replace(",", ""))
# End of _numcomma_to_num()
self._sort(column, reverse, _numcomma_to_num, self._sort_by_numcomma)
# End of _sort_by_num()
# End of class MyTreeview
objWindow = objTK.Tk()
arrlbHeader = ["Type" , "Description", "C. Name", "C. code", "Amount", "Day", "Month ", "Year", "Date", "Comments"]
treeview = MyTreeview(columns=arrlbHeader, show="headings")
arrRows = [["Expenses", "Curds milk", "Dairy products", "2.5.2.1", "456", "31", "8", "2021", "2021-08-31", ""],
["Expenses", "Aug", "Maid", "2.12.4", "1,000", "31", "8", "2021", "2021-08-31", ""],
["Expenses", "Aug", "Water", "2.12.8", "200", "31", "8", "2021", "2021-08-31", "AAA"],
["Income", "Aug", "Electricity", "2.12.2", "190", "31", "8", "2021", "2021-08-31", "OMG"],
["Expenses", "Aug - garbage collection", "Miscellaneous", "2.12.9", "20", "31", "8", "2021", "2021-08-31", "Test1"],
["Expenses", "Bread", "Bakery", "2.5.1.1", "10", "29", "8", "2021", "2021-08-29", ""],
["Income", "Veggies", "Vegetables", "2.5.2.7", "21", "28", "8", "2021", "2021-08-28", ""],
["Expenses", "Groceries", "Grains", "2.5.2.3", "76", "28", "8", "2021", "2021-08-28", "Test"],
["Expenses", "Phenyl", "Toiletries", "2.16", "34", "28", "8", "2021", "2021-08-28", ""]]
arrColWidth = [57, 53, 85, 69, 55, 30, 45, 33, 68, 100]
arrColAlignment = ["center", "e", "w", "w", "e", "center", "center", "center", "center", "w"]
arrSortType = ["name", "name", "name", "multidecimal", "numcomma", "num", "num", "num", "date", "name"]
for iCount in range(len(arrlbHeader)):
strHdr = arrlbHeader[iCount]
treeview.heading(strHdr, text=strHdr.title(), sort_by=arrSortType[iCount])
treeview.column(arrlbHeader[iCount], width=arrColWidth[iCount], stretch=True, anchor=arrColAlignment[iCount])
# End of for loop
treeview.pack()
for iCount in range(len(arrRows)):
treeview.insert("", "end", values=arrRows[iCount])
# End of for loop
objWindow.bind("<Escape>", lambda funcWinSer: objWindow.destroy())
objWindow.mainloop()
于 2021-09-23T04:35:27.090 回答