我正在尝试从我的数据库中获取信息并显示它。这是页面外观的屏幕截图：
页面加载真的很慢
有没有办法让它更快地加载和显示数据？
这是代码。
<table align="center" class="pTable">
<tr class="main"> <th class="pTableHeader"> ID </th> <th class="pTableHeader"> Room </th> <th class="pTableHeader"> Status</th> </tr>
<?php
gc_enable();
gc_collect_cycles();
flush();
$this->mysql = new sqli('HIDDEN','HIDDEN','HIDDEN','HIDDEN');
$bots = $this->mysql->fetch_array("SELECT `pid`,`room`,`id` from `bots`;");
foreach ($bots as $b) {
if(is_numeric($b["room"])) {
$xat = file_get_contents('http://www.xat.com/xat'.trim($b["room"]));
$name = sp($xat, '<h1> ', '</h1>');
}
else $name = $b['room'];
//$b["pid"] = isset($b["pid"])?$b["pid"]:false;
//$online = \"start.php {$b['id']} {$b['id']}\"", $output) && count($output) > 1 ? true : false;
$online = file_exists("/proc/{$b['pid']}" )?true:false;
if($online === true) $status = "<font color='green'>Online</font> <div style='float:right'><img src='http://fexbots.com/Images/Pawns/online.png'> <a href='/botinfo?botid={$b["id"]}'>More info</a></div>";
else $status = "<font color='red'>Offline</font> <div style='float:right'><img src='http://fexbots.com/Images/Pawns/offline.png'> <a href='/botinfo?botid={$b["id"]}'>More info</a></div>";
if($b["room"] === '') {
$name = "No Room";
$status = "<font color='red'>Not Setup!</font> <div style='float:right'><img src='http://fexbots.com/Images/Pawns/hang.png'> <a href='/botinfo?botid={$b["id"]}'>More info</a></div>";
echo '<tr> <td> '.$b["id"].' </td> <td> No Room <td> '.$status.'</td> </tr>';
}
else echo "<tr> <td> ".$b['id']." </td> <td> <a href='http://www.xat.com/$name'>$name</a> <td> ".$status."</td> </tr>";
}
function sp($content, $start, $end, $lower=false) {
if($lower!=false) {
$content = strtolower($content);
$start = strtolower($start);
$end = strtolower($end);
}
$content = substr($content, strpos($content,$start)+strlen($start));
$content = substr($content, 0, strpos($content,$end));
return $content;
}
?>
</table>