我想分解出angularjs $http 成功回调函数,这样我就有一个名为回调函数的函数,而不是两个(或 N 个)匿名回调函数。
这是两个控制器:
function CreateCurriculumCtrl($scope, $http, $location, select2Options){
$scope.curriculumInfo = {};
$scope.curriculumInfo.statusOK = true;
$scope.select2Options = select2Options;
$scope.saveCurriculum = function(){
$http.post('bignibou/curriculum/new', $scope.curriculumInfo).success(function(curriculumInfo) {
if(curriculumInfo.statusOK == true){
$scope.curriculumInfo.statusOK=true;
$location.path('/view/'+curriculumInfo.curriculum.id);
}
else{
$scope.curriculumInfo.statusOK = false;
$scope.curriculumInfo.errors = curriculumInfo.errors;
}
});
};
}
function EditCurriculumCtrl($scope, $http, $location, select2Options, $routeParams){
$scope.curriculumInfo = {};
$scope.curriculumInfo.statusOK = true;
$scope.select2Options = select2Options;
$scope.id = $routeParams.id;
$http.get('/bignibou/utils/findCurriculumById.json',{params: {id: $routeParams.id}}).success(
function(curriculum){
$scope.curriculumInfo.curriculum = curriculum;
});
$scope.editCurriculum = function(){
$http.post('bignibou/curriculum/edit/'+$routeParams.id, $scope.curriculumInfo)
.success(function(curriculumInfo) {
if(curriculumInfo.statusOK == true){
$scope.curriculumInfo.statusOK=true;
$location.path('/view/'+curriculumInfo.curriculum.id);
}
else{
$scope.curriculumInfo.statusOK = false;
$scope.curriculumInfo.errors = curriculumInfo.errors;
}
});
};
}
我不知道该怎么做,因为命名的回调函数有几个依赖项(即$scope 和$location)。
如果我从 angularjs 控制器中提取函数(命名回调),则命名回调不再访问其依赖项。
任何人都可以帮助分解成功回调函数并确保满足依赖关系吗?