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我正在尝试遍历 2D 列表，并取决于因素，附加到行或删除整行

如果tempX匹配某个值，tempX并且tempY应该追加到列表中的当前行。如果tempX与该值不匹配，则应从列表中删除整行。

这是到目前为止的代码。

aList = [[1,2,3,4,5],[6,7,8,9,10],[11,12,13,14,15]]

i = 0

for a, b, c, d, e in aList[:]:

    tempC = c
    tempD = D

    tempX = tempC * 2 # These are just a placeholders for another calculation
    tempY = tempD * 2

    if tempX <= 10:
        aList[i].append(tempX)
        aList[i].append(tempY)
    else:
        del aList[i] 

    i += 1

预期结果： aList = [[6, 7, 8, 9, 10, 16, 18], [11, 12, 13, 14, 15, 26, 28]]

相反，这会导致

ValueError: too many values to unpack

编辑

经过一番研究，我得出了这个解决方案。

关键是bList = aList[::-1]；这将列表拼接成相反的顺序，消除了前面示例中的情况，即我有效地试图在没有千斤顶的情况下从汽车上取下轮胎。

aList = [[1,2,3,4,5],[6,7,8,9,10],[11,12,13,14,15],[16,17,18,19,20],[21,22,23,24,25],[26,27,28,29,30]]
bList = aList[::-1]

i = 0

for a, b, c, d, e in bList:
    tempC = c
    tempD = d

    tempX = tempC * 2
    tempY = tempD * 2

    if tempX >= 50:
        bList[i].append(tempX)
        bList[i].append(tempY)
    else:
        del bList[i]

    i += 1

print bList

这将是一个很好的解决方案，除了它每隔两行跳过一次。我不太确定是什么导致它跳过行。

[[26, 27, 28, 29, 30, 56, 58], [21, 22, 23, 24, 25], [16, 17, 18, 19, 20], [11, 12, 13, 14, 15], [6, 7, 8, 9, 10], [1, 2, 3, 4, 5]]
[[26, 27, 28, 29, 30, 56, 58], [16, 17, 18, 19, 20], [11, 12, 13, 14, 15], [6, 7, 8, 9, 10], [1, 2, 3, 4, 5]]
[[26, 27, 28, 29, 30, 56, 58], [16, 17, 18, 19, 20], [6, 7, 8, 9, 10], [1, 2, 3, 4, 5]]
[[26, 27, 28, 29, 30, 56, 58], [16, 17, 18, 19, 20], [6, 7, 8, 9, 10]]

预期结果： bList = [[26, 27, 28, 29, 30, 56, 58]]应删除所有其他行

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1 回答 1

1

在不偏离您的代码太远的情况下......

aList = [[1,2,3,4,5],[6,7,8,9,10],[11,12,13,14,15],[16,17,18,19,20],[21,22,23,24,25],[26,27,28,29,30]]
bList = []

i = 0

for a, b, c, d, e in aList:
    tempC = c
    tempD = d

    tempX = tempC * 2
    tempY = tempD * 2

    if tempX >= 50:
        bList.append(aList[i]+ [tempX,tempY])
    i += 1

print bList
于 2013-10-29T14:56:11.887 回答