我想编写一个使用 Python 的smtplib发送电子邮件的程序。我搜索了文档和 RFC,但找不到与附件相关的任何内容。因此,我确信我错过了一些更高层次的概念。有人能告诉我附件在 SMTP 中是如何工作的吗?
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6 回答
32
以下是带有 PDF 附件、文本“正文”并通过 Gmail 发送的邮件示例。
# Import smtplib for the actual sending function
import smtplib
# For guessing MIME type
import mimetypes
# Import the email modules we'll need
import email
import email.mime.application
# Create a text/plain message
msg = email.mime.Multipart.MIMEMultipart()
msg['Subject'] = 'Greetings'
msg['From'] = 'xyz@gmail.com'
msg['To'] = 'abc@gmail.com'
# The main body is just another attachment
body = email.mime.Text.MIMEText("""Hello, how are you? I am fine.
This is a rather nice letter, don't you think?""")
msg.attach(body)
# PDF attachment
filename='simple-table.pdf'
fp=open(filename,'rb')
att = email.mime.application.MIMEApplication(fp.read(),_subtype="pdf")
fp.close()
att.add_header('Content-Disposition','attachment',filename=filename)
msg.attach(att)
# send via Gmail server
# NOTE: my ISP, Centurylink, seems to be automatically rewriting
# port 25 packets to be port 587 and it is trashing port 587 packets.
# So, I use the default port 25, but I authenticate.
s = smtplib.SMTP('smtp.gmail.com')
s.starttls()
s.login('xyz@gmail.com','xyzpassword')
s.sendmail('xyz@gmail.com',['xyz@gmail.com'], msg.as_string())
s.quit()
于 2011-11-23T13:32:07.977 回答
19
这是我从我们所做的工作应用程序中截取的一个示例。它创建一个带有 Excel 附件的 HTML 电子邮件。
import smtplib,email,email.encoders,email.mime.text,email.mime.base
smtpserver = 'localhost'
to = ['email@somewhere.com']
fromAddr = 'automated@hi.com'
subject = "my subject"
# create html email
html = '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" '
html +='"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml">'
html +='<body style="font-size:12px;font-family:Verdana"><p>...</p>'
html += "</body></html>"
emailMsg = email.MIMEMultipart.MIMEMultipart('alternative')
emailMsg['Subject'] = subject
emailMsg['From'] = fromAddr
emailMsg['To'] = ', '.join(to)
emailMsg['Cc'] = ", ".join(cc)
emailMsg.attach(email.mime.text.MIMEText(html,'html'))
# now attach the file
fileMsg = email.mime.base.MIMEBase('application','vnd.ms-excel')
fileMsg.set_payload(file('exelFile.xls').read())
email.encoders.encode_base64(fileMsg)
fileMsg.add_header('Content-Disposition','attachment;filename=anExcelFile.xls')
emailMsg.attach(fileMsg)
# send email
server = smtplib.SMTP(smtpserver)
server.sendmail(fromAddr,to,emailMsg.as_string())
server.quit()
于 2009-12-27T16:03:46.780 回答
12
您要检查的是email
模块。它允许您构建符合MIME的消息,然后使用 smtplib 发送这些消息。
于 2009-12-27T14:39:32.440 回答
3
以下是发送带有 zip 文件附件和 utf-8 编码主题+正文的电子邮件的方法。
由于缺乏针对此特定案例的文档和示例,因此很难弄清楚这一点。
回复中的非 ascii 字符需要使用例如 ISO-8859-1 进行编码。可能存在可以执行此操作的功能。
提示:
给自己发送一封电子邮件,保存并检查内容以找出如何在 Python 中做同样的事情。
这是 Python 3 的代码:
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
# vim:set ts=4 sw=4 et:
from os.path import basename
from smtplib import SMTP
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email.mime.multipart import MIMEMultipart
from email.header import Header
from email.utils import parseaddr, formataddr
from base64 import encodebytes
def send_email(recipients=["somebody@somewhere.xyz"],
subject="Test subject æøå",
body="Test body æøå",
zipfiles=[],
server="smtp.somewhere.xyz",
username="bob",
password="password123",
sender="Bob <bob@somewhere.xyz>",
replyto="=?ISO-8859-1?Q?M=F8=F8=F8?= <bob@somewhere.xyz>"): #: bool
"""Sends an e-mail"""
to = ",".join(recipients)
charset = "utf-8"
# Testing if body can be encoded with the charset
try:
body.encode(charset)
except UnicodeEncodeError:
print("Could not encode " + body + " as " + charset + ".")
return False
# Split real name (which is optional) and email address parts
sender_name, sender_addr = parseaddr(sender)
replyto_name, replyto_addr = parseaddr(replyto)
sender_name = str(Header(sender_name, charset))
replyto_name = str(Header(replyto_name, charset))
# Create the message ('plain' stands for Content-Type: text/plain)
try:
msgtext = MIMEText(body.encode(charset), 'plain', charset)
except TypeError:
print("MIMEText fail")
return False
msg = MIMEMultipart()
msg['From'] = formataddr((sender_name, sender_addr))
msg['To'] = to #formataddr((recipient_name, recipient_addr))
msg['Reply-to'] = formataddr((replyto_name, replyto_addr))
msg['Subject'] = Header(subject, charset)
msg.attach(msgtext)
for zipfile in zipfiles:
part = MIMEBase('application', "zip")
b = open(zipfile, "rb").read()
# Convert from bytes to a base64-encoded ascii string
bs = encodebytes(b).decode()
# Add the ascii-string to the payload
part.set_payload(bs)
# Tell the e-mail client that we're using base 64
part.add_header('Content-Transfer-Encoding', 'base64')
part.add_header('Content-Disposition', 'attachment; filename="%s"' %
os.path.basename(zipfile))
msg.attach(part)
s = SMTP()
try:
s.connect(server)
except:
print("Could not connect to smtp server: " + server)
return False
if username:
s.login(username, password)
print("Sending the e-mail")
s.sendmail(sender, recipients, msg.as_string())
s.quit()
return True
def main():
send_email()
if __name__ == "__main__":
main()
于 2010-01-29T10:17:11.293 回答
1
# -*- coding: utf-8 -*-
"""
Mail sender
"""
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
import smtplib
import pystache
import codecs
import time
import sys
reload(sys)
sys.setdefaultencoding('utf-8')
HOST = 'smtp.exmail.qq.com'
PORT = 587
USER = 'your@mail.com'
PASS = 'yourpass'
FROM = 'your@mail.com'
SUBJECT = 'subject'
HTML_NAME = 'tpl.html'
CSV_NAME = 'list.txt'
FAILED_LIST = []
def send(mail_receiver, mail_to):
# text = mail_text
html = render(mail_receiver)
# msg = MIMEMultipart('alternative')
msg = MIMEMultipart('mixed')
msg['From'] = FROM
msg['To'] = mail_to.encode()
msg['Subject'] = SUBJECT.encode()
# msg.attach(MIMEText(text, 'plain', 'utf-8'))
msg.attach(MIMEText(html, 'html', 'utf-8'))
try:
_sender = smtplib.SMTP(
HOST,
PORT
)
_sender.starttls()
_sender.login(USER, PASS)
_sender.sendmail(FROM, mail_to, msg.as_string())
_sender.quit()
print "Success"
except smtplib.SMTPException, e:
print e
FAILED_LIST.append(mail_receiver + ',' + mail_to)
def render(name):
_tpl = codecs.open(
'./html/' + HTML_NAME,
'r',
'utf-8'
)
_html_string = _tpl.read()
return pystache.render(_html_string, {
'receiver': name
})
def main():
ls = open('./csv/' + CSV_NAME, 'r')
mail_list = ls.read().split('\r')
for _receiver in mail_list:
_tmp = _receiver.split(',')
print 'Mail: ' + _tmp[0] + ',' + _tmp[1]
time.sleep(20)
send(_tmp[0], _tmp[1])
print FAILED_LIST
main()
于 2016-11-02T16:08:00.407 回答