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我有以下代码（使用 graphviz4net 从 C# 转换而来）：

digraph g {
graph [rankdir="LR" ,compound="true" ];
    subgraph cluster0 {
        graph [label="Ready" ];
        1 [  ];
    };
    subgraph cluster2 {
        graph [label="Paused" ];
        3 [  ];
    };
    1 -> 3 [ ltail="cluster0" ,lhead="cluster2" ,comment="4"  ];
    3 -> 1 [ ltail="cluster2" ,lhead="cluster0" ,comment="5"  ];
}

我正在http://www.graphviz-dev.appspot.com/上检查转换后的图像。

图像是这样的：

使用 Graphviz 转换的图像

我正在用 C# 编程。我有两个问题：

1 - 如何修复 C# 中的箭头？

2 - 如何使省略号在 C# 中消失？

*我知道我可以使用节点 [shape = none]，但我不知道如何在 C# 中设置它。

更新：

现在我有以下代码：

digraph g {
graph [rankdir="LR" ,compound="true" ];
    subgraph cluster0 {
        graph [label="Ready\n\nPurchaser:\noperation1,operation2,Supplier:\noperation1,operation3," ];
        1 [ shape="none" ,fontcolor="white"  ];
    };
    subgraph cluster2 {
        graph [label="Paused\n\nPurchaser:\noperation1,operation3,Supplier:\noperation2,operation3," ];
        3 [ shape="none" ,fontcolor="white"  ];
    };
    subgraph cluster4 {
        graph [label="Completed\n\nPurchaser:\noperation4,Supplier:\noperation4," ];
        5 [ shape="none" ,fontcolor="white"  ];
    };
    1 -> 3 [ ltail="cluster0" ,lhead="cluster2" ,comment="6"  ];
    1 -> 5 [ ltail="cluster0" ,lhead="cluster4" ,comment="7"  ];
    3 -> 1 [ ltail="cluster2" ,lhead="cluster0" ,comment="8"  ];
    3 -> 5 [ ltail="cluster2" ,lhead="cluster4" ,comment="9"  ];
}

这给了我：

Graphviz4net

不用担心标签问题，我会解决的。

C#代码如下：

Graph<State> Graph = new Graph<State> { Rankdir = RankDirection.LeftToRight };

stringBuilder 生成子图

// returns new SubGraph<State>{ Label = stringBuilder.ToString()};
var stringNewBlock = ConvertBlockToSubgraph(state);

ConvertBlockToSubgraph 内部

foreach (var allowedOperation in allowedOperationList)
            {
                stringBuilder.Append(allowedOperation.Key +":\\n");

                foreach (var operation in allowedOperation.Value)
                {
                    stringBuilder.Append(!operation.Equals(lastAllowedOperation) ? operation + ",": operation);
                }
            }

回到外面的世界：

var subgraphNewBlock = new SubGraph<State>{ Label = stringBuilder.ToString()};


stringNewBlock.AddVertex(state);
Graph.AddSubGraph(stringNewBlock);

然后我生成边缘：

public override IBlockHandling<State> GenerateLinks()
{
    foreach (var state in statesDictionary.Values)
    {
        foreach (var nextPossibleState in state.GetNextPossibleStateList())
        {
            if (statesDictionary.ContainsKey(nextPossibleState))
            {
                var sourceSubGraph = Graph.SubGraphs.Single(x => x.Label.Contains(state.GetMainHeaderName()));
                var destinationSubGraph = Graph.SubGraphs.Single(x => x.Label.Contains(nextPossibleState));
                var edge = new Edge<SubGraph<State>>(sourceSubGraph, destinationSubGraph);
                Graph.AddEdge(edge);
            }

        }
    }

    return this;
}

然后我转换为 DOT 格式：

    public override IBlockHandling<State> ConvertDtoToDot()
    {
        var writer = new StringWriter();
        new GraphToDotConverter().Convert(writer, Graph, new AttributesProvider());
        var result = writer.GetStringBuilder().ToString().Trim();

        Console.WriteLine(result);

        return this;
    }

我仍然遇到的问题是箭头看起来很奇怪。

有什么建议么？

4

1 回答 1

1

如果你给你的边缘多一点空间，箭头看起来会很好。实现这一点的最简单方法是使用nodeep 属性

graph [nodesep=2];

结果将是：

在此处输入图像描述

如果您在使用的 Graphviz C# 库中一直遇到有关如何执行此操作的问题，您应该考虑让您的代码生成 DOT 代码并将其提供给 graphviz。DOT 是DSL是有原因的；-)

于 2013-11-02T10:25:15.100 回答