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我对 Oracle 很陌生（几个小时）。我的经验全是 MySQL。

我的查询在我看来是非常基本的，但是 group by 似乎并没有返回预期的结果。经过几个小时的搜索，我希望这里有人可以提供帮助！

这是我的代码：

SELECT trunc(start_time), display_name, count(*)
FROM TblName
WHERE (DISPLAY_NAME like '%Advise the customer how they can change their marketing preferences%')
      OR (DISPLAY_NAME like '%Inform customer on relevant ads%')
      OR (DISPLAY_NAME like '%Is the customer requesting to block%')
GROUP BY start_time, display_name
HAVING start_time >= '2013-10-24';

我得到的结果将有多个行，它们具有相同的 start_time、display_name 和 1 的计数。超过 400 行在查询中返回并且所有的计数都为 1。

编辑：以下是结果。所以我现在明白为什么 group by 不能正常工作。在 MySQL 中，我会使用 date(start_time) 来纠正这个问题。甲骨文有类似的东西吗？

11-SEP-13 02.16.42.809000000 PM Advise the customer how they can change their marketing preferences.    1
25-SEP-13 11.56.05.814000000 AM Advise the customer how they can change their marketing preferences.    1
26-SEP-13 11.17.29.737000000 AM Advise the customer how they can change their marketing preferences.    1
24-OCT-13 10.53.17.941000000 AM Advise the customer how they can change their marketing preferences.    1
26-OCT-13 10.24.25.099000000 AM Is the customer requesting to block?    1
23-OCT-13 08.28.58.234000000 PM Advise the customer how they can change their marketing preferences.    1
25-OCT-13 02.50.49.329000000 PM Inform customer on relevant ads 1
26-OCT-13 11.46.45.686000000 AM Advise the customer how they can change their marketing preferences.    1
28-OCT-13 10.12.31.613000000 AM Inform customer on relevant ads 1
25-OCT-13 11.38.24.570000000 AM Inform customer on relevant ads 1

提前致谢！

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1 回答 1

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您需要将您的 trunc(start_time) 应用到组中，如下所示：

SELECT trunc(start_time), display_name, count(*)
FROM TblName
WHERE (DISPLAY_NAME like '%Advise the customer how they can change their marketing preferences%')
      OR (DISPLAY_NAME like '%Inform customer on relevant ads%')
      OR (DISPLAY_NAME like '%Is the customer requesting to block%')
GROUP BY trunc(start_time), display_name
HAVING trunc(start_time) >= '2013-10-24';
于 2013-10-29T01:33:14.970 回答