php - 通过 PHP 将数据插入 MySQL 表时出错

Question

我有一个带有“AllParties”表的 MySQL 数据库。当我使用 PHP（如下）将数据插入到该表中时，我没有收到错误，但是，数据没有插入到表中。我尝试从 MySQL 服务器获取错误报告，但很模糊，它说 MySQL 语法有错误。请注意我在 Mac CodeRunner 中运行我的代码，这可能是问题所在？此外，$con 是一个成功的连接。

<?php
$con=mysqli_connect("sql3.freemysqlhosting.net","*********","********","*********");

$name = "Will's Party";
$date = 'October 1st, 2013';
$housenum = '333 East Street';
$city = "Golden Gate";
$state = "California"; 
$time = "7:00";
$tag = "Serra";

mysqli_select_db('AllParties', $con);

$alpha = mysqli_query($con, 'INSERT INTO AllParties(Party Name, Date, House number and       street name, City, State, Time, Tag)  VALUES("$name","$date","$housenum","$city","$state","$time","$tag")');
?>

Answer 1

任何包含空格的列名，以及像这样命名列是让开发人员非常沮丧的好方法，都需要转义：

INSERT INTO AllParties (`Party Name`, ...)

反引号，而不是常规引号，用于转义数据库、表和列名。常规引号'，"用于字符串。

Answer 2

<?php
$con=mysqli_connect("sql3.freemysqlhosting.net","*********","********","*********");

$name = 'Will\'s Party';
$date = 'October 1st, 2013';
$housenum = '333 East Street';
$city = 'Golden Gate';
$state = 'California'; 
$time = '7:00';
$tag = 'Serra';

mysqli_select_db('AllParties', $con);

$alpha = mysqli_query($con, "INSERT INTO AllParties(`Party Name`, `Date`, `House   number and street name`, `City`, `State`, `Time`, `Tag`)    VALUES('{$name}','{$date}','{$housenum}','{$city}','{$state}','{$time}','{$tag}')");
?>

{$x} 将评估 x 字符串