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我是hibernate和JPA的新手,我正在尝试做下一件事:

public class Centre extends JpaStandardVersionableEntity {
@Id
@GeneratedValue(strategy = GenerationType.AUTO, generator = "sq")
@SequenceGenerator(name = "sq", sequenceName = SQ_NAME)
@Column(name = "ID_CTR", nullable = false)
private Integer idCtr;
        ...

@JoinColumn(name = "ID_DRC", referencedColumnName = "ID_DRC", nullable = false)
@ManyToOne(cascade = CascadeType.ALL, optional = false, fetch = FetchType.LAZY)
private Address idDrc;

}


public class Address extends JpaStandardVersionableEntity {
@Id
@GeneratedValue(strategy = GenerationType.AUTO, generator = "sq")
@SequenceGenerator(name = "sq", sequenceName = SQ_NAME)
@Column(name = "ID_DRC", nullable = false)
private Integer idDrc;
}

使用级联 ALL 以便在我注册中心时插入地址。

但是我遇到了这个错误:违反完整性约束 FK_CTR_DRC - 找不到父键

似乎这没有按预期工作......有什么想法吗?提前致谢

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1 回答 1

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片段是正确的。我的问题实际上与地址触发器有关。给您带来的不便深表歉意。

于 2013-10-31T08:35:45.103 回答