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我有 UIWebView 用于显示 HTML 文章页面。我使用 UILongPressGesture 来获取触摸位置坐标。我将这些坐标保存到数据库中。每个坐标都有按钮。现在我需要在单击按钮时从数据库中删除这些坐标之一。所以，在这里我从数据库中获取坐标并且坐标与当前位置匹配，然后我删除特定的坐标按钮。但它没有删除

 if(x1 && y1){

        NSLog(@"x1 is %f",x1);
        NSLog(@"y1 is %f",y1);


        sqlite3_stmt *addStmt;

       // const char *sqlDelete = "DELETE xcoor,ycoor FROM touch";


         const char *sqlDelete = [[NSString stringWithFormat:@"delete FROM touch where xcoor = '%f','%f'",x1,y1] cStringUsingEncoding:NSUTF8StringEncoding];

        if(sqlite3_prepare_v2(database, sqlDelete, -1, &addStmt, NULL) != SQLITE_OK)
            NSAssert1(0, @"Error while deleting coor from touch . '%s'", sqlite3_errmsg(database));

        NSLog(@"%s error finalizing %s", __FUNCTION__, sqlite3_errmsg(database));

        if(SQLITE_DONE != sqlite3_step(addStmt))
            NSAssert1(0, @"Error while deleting coor from touch . '%s'", sqlite3_errmsg(database));


}

x1 & y1 是当前位置坐标

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1 回答 1

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const char *sqlDelete = [[NSString stringWithFormat:@"delete FROM touch where xcoor = %f AND ycoor = %f",x1,y1] cStringUsingEncoding:NSUTF8StringEncoding];

用这个替换你的删除语句它会起作用

于 2013-10-28T08:37:33.897 回答