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在我的 MySQL 数据库上有 3 个不同的表：专辑、单曲、即将到来的。我想通过 php 嵌入所有三个。只有我嵌入的第一个表适用于以下代码，另一个不适用：

<div id="album_releases" class="animated bounceIn">

            <div id="headline">Latest Favorite Album Releases</div>

            <div id="frame" class="frame">

            <ul class="slidee">

                <li><div id="datebox"><span style="padding-top:50px;">Oct<br />2013</span></div></li>    

                            <?php

                $sql = "SELECT artist, releasename, label, date, img, spotify, nas, itunes FROM album ORDER BY id DESC LIMIT 40";

                $db_erg = $db_link->query( $sql );


                function ausgabe($daten) {
                    echo "<li><div id='blurbox'><div class='blur img'><div class='img-wrap'><div class='img-info'>";
                    echo "". $daten->artist ."<br />";
                    echo "". $daten->releasename ."<br />";
                    echo "". $daten->label ."<br />";
                    echo "". $daten->date ."<br />";
                    echo "</div>";
                    echo "<img class='hover' width='168' height='168' src=". $daten->img .">";
                    echo "</div></div></div><div id='caption'>";
                    echo "<img src='images/spotifyicon.png' style='float:left;'><a href='". $daten->spotify ."'>Listen on Spotify</a><br />";
                    echo "<div id='element_sep'>-</div>";
                    echo "<img src='images/servericon.png' style='float:left;'><a href='". $daten->nas ."'>Listen on toegrNAS</a><br />";
                    echo "<div id='element_sep'>-</div>";
                    echo "<img src='images/itunesicon.png' style='float:left;'><a href='". $daten->itunes ."'>Listen/Buy on iTunes</a>";
                    echo "</div></li>";
                }

                while($daten = $db_erg->fetch_object()) {
                    ausgabe($daten);
                }

                ?>

            </ul>

          </div>          

          <div id="overlay_left">-</div>

          <div id="overlay_right">-</div>

        </div>

        <div id="single_releases" class="animated bounceIn">

            <div id="headline">Latest Favorite Single Releases</div>

            <div id="frame" class="frame">

            <ul class="slidee">

                <li><div id="datebox"><span style="padding-top:50px;">Oct<br />2013</span></div></li>

                            <?php

                $sql = "SELECT artist, releasename, label, date, img, spotify, nas, itunes FROM single ORDER BY id DESC LIMIT 40";

                $db_erg = $db_link->query( $sql );


                function ausgabe($daten) {
                    echo "<li><div id='blurbox'><div class='blur img'><div class='img-wrap'><div class='img-info'>";
                    echo "". $daten->artist ."<br />";
                    echo "". $daten->releasename ."<br />";
                    echo "". $daten->label ."<br />";
                    echo "". $daten->date ."<br />";
                    echo "</div>";
                    echo "<img class='hover' width='168' height='168' src=". $daten->img .">";
                    echo "</div></div></div><div id='caption'>";
                    echo "<img src='images/spotifyicon.png' style='float:left;'><a href='". $daten->spotify ."'>Listen on Spotify</a><br />";
                    echo "<div id='element_sep'>-</div>";
                    echo "<img src='images/servericon.png' style='float:left;'><a href='". $daten->nas ."'>Listen on toegrNAS</a><br />";
                    echo "<div id='element_sep'>-</div>";
                    echo "<img src='images/itunesicon.png' style='float:left;'><a href='". $daten->itunes ."'>Listen/Buy on iTunes</a>";
                    echo "</div></li>";
                }

                while($daten = $db_erg->fetch_object()) {
                    ausgabe($daten);
                }

?>    

            </ul>

          </div>          

          <div id="overlay_left">-</div>

          <div id="overlay_right">-</div>

        </div>

        <div id="upcoming_releases" class="animated bounceIn">

            <div id="headline">Upcoming Releases</div>  

                    <div class="content">

                        <div id="release_element">

                                        <?php
            require_once ('mysql-config.php');

            $db_link = mysqli_connect (
                                     MYSQL_HOST, 
                                     MYSQL_BENUTZER, 
                                     MYSQL_KENNWORT, 
                                     MYSQL_DATENBANK
                                    );

                $sql = "SELECT date, artist, releasename, itunes, ical, directdl FROM upcoming ORDER BY id DESC LIMIT 40";

                $db_erg = $db_link->query( $sql );

                function ausgabe($daten) {
                    echo "<img src='images/icon_cd.png'>";
                    echo "<span class='release_bold'>". $daten->date .":&nbsp;". $daten->artist ."&nbsp;-&nbsp;". $daten->releasename ."</span><br />";
                    echo "<span class='release_grey'><a href='". $daten->itunes ."'>iTunes (Pre-Order)</a>&nbsp;-&nbsp;<a href='". $daten->ical ."'>Create iCal-Event</a>&nbsp;-&nbsp;<a href='". $daten->directdl ."'>Download</a></span><br />";
                }

                while($daten = $db_erg->fetch_object()) {
                    ausgabe($daten);
                }

                ?>

当我尝试嵌入其他两个表时，页面只显示一个白屏。问题是，如何通过 php 在不同位置嵌入三个不同的 mysql 表？

谢谢

项目链接： http: //toegraphics.de/music/

4

1 回答 1

0

这应该在文件的开头，而不是第三种情况。

require_once ('mysql-config.php');

$db_link = mysqli_connect (
                                     MYSQL_HOST, 
                                     MYSQL_BENUTZER, 
                                     MYSQL_KENNWORT, 
                                     MYSQL_DATENBANK
                                    );

否则 $db_link 未定义，并且在未定义对象上调用以下方法时会出错。您什么都看不到的原因可能是因为您的网络服务器错误消息被禁用。

$db_link->query( $sql );

您还定义了 3 次函数。您必须使用不同的名称。

function ausgabe($daten)
于 2013-10-27T20:12:28.580 回答