0

基本上我需要为这个数学测验做的最后一件事是我必须编程，我必须询问用户他们是否想回答更多问题，如果是，重新运行 Main Method 中的所有内容。如果没有，请打印再见。否很容易，但我不确定如果他们说是，我不确定如何告诉它重新运行 main 方法。这是我的主要方法中的代码。

 public static void main(String[] args) {
    Scanner in = new Scanner(System.in);

    int digit = 0;

    String result1 = getUserChoice("");

    digit = getNumberofDigit1(digit);

    int numberOfProblems = amountOfProblems();

    for (int i = 0; i < numberOfProblems; i++) {
    int number1 = getRandomNumber1(digit);
    int number2 = getRandomNumber2(digit);

    System.out.println("Enter your answer to the following problem: \n" + 
            number1 + result1 + number2);
    int correctAnswer = getCorrectAnswer(number1, result1, number2);

    int userAnswer = getUserAnswer();

    CheckandDisplayResult(correctAnswer, userAnswer);
    }
        System.out.println("Would you like to solve more probelms(Y/N)? ");
        String moreProblems = in.next();

        if ("Y".equals(moreProblems)){
            digit = 0;

    result1 = getUserChoice("");

    digit = getNumberofDigit1(digit);

    numberOfProblems = amountOfProblems();

    for (int i = 0; i < numberOfProblems; i++) {
    int number1 = getRandomNumber1(digit);
    int number2 = getRandomNumber2(digit);

    System.out.println("Enter your answer to the following problem: \n" + 
            number1 + result1 + number2);
    int correctAnswer = getCorrectAnswer(number1, result1, number2);

    int userAnswer = getUserAnswer();

    CheckandDisplayResult(correctAnswer, userAnswer);
    }
        System.out.println("Would you like to solve more probelms(Y/N)? ");
        moreProblems = in.next();

          if ("Y".equals(moreProblems)){

        }
        System.out.println("Thank you for taking this quiz, Goodbye!");

}

现在我尝试了类似的东西，

if "Y".equals(moreProblems)){ 复制并过去 main 方法}

但这有一个需要无限循环的错误，因为您必须在每个“是”的情况下都有更多的问题陈述，这意味着它永远不会以明智的方式结束编码，您将永远保持复制和粘贴。

4

5 回答 5

3

您可以将所有要“重新运行”的代码包含在 while 循环中：

boolean run = true;
while (run) {
    // Here your code
    // Here input if user want to re-run
    if (getUserChoice("").equals("NO"))
        run = false;
}
于 2013-10-27T04:27:25.723 回答
2

替代其他人的建议，这是我更喜欢的方法：

while(true) {
    //do all your stuff
    if(/*some exit condition*/) { break; }
}
于 2013-10-27T04:30:30.613 回答
1

您可以做的是将所有内容main()移入另一个静态方法，调用它interact()。然后在 中，只要用户想与您的程序交互main()，就可以调用逻辑。interact()换句话说，将数学测验放在一种方法中，将提出测验的业务放在main(). 如果需要，您的程序将更易于阅读并且更易于进一步修改。

于 2013-10-27T04:26:33.403 回答
1

将所有这些放在一个大的 do-while 循环中：

boolean more = false;

do {

    // all your code

    more = "Y".equals(moreProblems);

} while (more);

或者，如果您的 Scanner 在循环之外声明，您可以：

do {

    // all your code

} while ("Y".equals(in.next()));
于 2013-10-27T04:27:46.850 回答
0

我想这个原型可能会对你有所帮助

import java.util.Scanner;
 public class MathsClass {
    public static void main(String[] args){
        MathsClass object = new MathsClass();

        while(object.response())
            object.mathsQuiz();

    }

    public void mathsQuiz(){
        //your quiz functionalities
        System.out.println("Add two nos");
    }

    public boolean response(){
        System.out.println("Would u like to solve more problems? ");
        Scanner scanner = new Scanner(System.in);
        boolean response = scanner.nextBoolean();

        return response;
    }
}
于 2013-10-27T04:39:38.547 回答