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I made a JS Fiddle to demonstrate this problem: http://jsfiddle.net/8uC4Z/1/

Why does ga.getAll() only have one tracker instead of two? I am following the instructions here: https://developers.google.com/analytics/devguides/collection/analyticsjs/advanced

/* https://developers.google.com/analytics/devguides/collection/analyticsjs/advanced */

(function(i,s,o,g,r,a,m){i['GoogleAnalyticsObject']=r;i[r]=i[r]||function(){
  (i[r].q=i[r].q||[]).push(arguments)},i[r].l=1*new Date();a=s.createElement(o),
  m=s.getElementsByTagName(o)[0];a.async=1;a.src=g;m.parentNode.insertBefore(a,m)
  })(window,document,'script','//www.google-analytics.com/analytics.js','ga');

ga('create', 'UA-42441200-1', 'domain1');
ga('send', 'pageview'); // first one created is the default

ga('create', 'UA-35320164-1 ', 'domain2');
ga('domain2.send', 'pageview');

ga(function() {
    console.log("The following is the array of all trackers:");
    console.log(ga.getAll());
    console.log("Why is there only 1 in the array?");
}); // why only 1 snippet?
4

2 回答 2

2

跟进@Steven V的回答......

只能有一个未命名（默认）的跟踪器。当第三个参数为字符串时：

ga('create', 'UA-42441200-1', 'domain1');

我猜这是设置跟踪器 cookieDomain 的快捷方式，而不是跟踪器名称。

您可以使用第一个跟踪器的快捷方式代码，但必须明确命名第二个：

ga('create', 'UA-42441200-1', 'domain1');
ga('send', 'pageview'); // first one created is the default
ga('create', 'UA-35320164-1', {'name': 't2'});
ga('t2.send', 'pageview');
于 2013-10-27T16:18:31.790 回答
1

阅读文档，正确的语法是：

ga('create', 'UA-12345-6', {'name': 'newTracker'});

其中第三个参数是一个对象，而不是一个字符串。

ga('create', 'UA-42441200-1', {'name': 'domain1'});
ga('create', 'UA-35320164-1 ', {'name': 'domain2'});

ga.getAll()返回两个对象对我有用。

于 2013-10-27T01:12:14.150 回答