43

我想在一个页面上有几个日期选择器。但是使用 UI-Bootstrap 的默认解决方案是不可能的，任何一个日期选择器都不能打开。彼此的冲突。这是我的代码：

<div>
            <div class="form-horizontal pull-left">
                <input type="text" datepicker-popup="dd-MMMM-yyyy" ng-model="dt" is-open="opened" min="minDate" max="'2015-06-22'" datepicker-options="dateOptions" date-disabled="disabled(date, mode)" ng-required="true"/>
                <button class="btn" ng-click="open()"><span class="glyphicon glyphicon-calendar"></span></button>
            </div>
            <div class="form-horizontal pull-left">
                <input type="text" datepicker-popup="dd-MMMM-yyyy" ng-model="dt" is-open="opened" min="minDate" max="'2015-06-22'" datepicker-options="dateOptions" date-disabled="disabled(date, mode)" ng-required="true" />
                <button class="btn" ng-click="open()"><span class="glyphicon glyphicon-calendar"></span></button>
            </div>
            <button type="submit" class="btn btn-default">Submit</button>
        </div>

我刚刚从网站http://angular-ui.github.io/bootstrap/#/datepicker复制/粘贴了 datepicker 代码。它们相互冲突。当我单击<input>字段打开日期选择器时，没有人可以正确打开，两者都会打开一秒钟并立即消失。

如何在一个页面上有多个日期选择器？

4

7 回答 7

79

is-open您可以使用不同的属性，然后通过函数传递属性，而不是使用不同的ng-click函数。您仍然需要不同的模型：

<div>
        <div class="form-horizontal pull-left">
            <input type="text" datepicker-popup="dd-MMMM-yyyy" ng-model="dt1" is-open="opened1" min="minDate" max="'2015-06-22'" datepicker-options="dateOptions" date-disabled="disabled(date, mode)" ng-required="true"/>
            <button class="btn" ng-click="open($event,'opened1')"><span class="glyphicon glyphicon-calendar"></span></button>
        </div>
        <div class="form-horizontal pull-left">
            <input type="text" datepicker-popup="dd-MMMM-yyyy" ng-model="dt2" is-open="opened2" min="minDate" max="'2015-06-22'" datepicker-options="dateOptions" date-disabled="disabled(date, mode)" ng-required="true" />
            <button class="btn" ng-click="open($event,'opened2')"><span class="glyphicon glyphicon-calendar"></span></button>
        </div>
        <button type="submit" class="btn btn-default">Submit</button>
    </div>

和内部控制器：

   $scope.open = function($event,opened) {
    $event.preventDefault();
    $event.stopPropagation();

    $scope[opened] = true;
  };
于 2014-02-18T21:25:57.467 回答
15

我仍在学习 Angular 和 UI-Bootstrap，所以在阅读我的答案时要考虑到这一点。我做了一些类似于 BlueMonk 的事情，但以一种灵活的方式使我的控制器代码不必知道页面上的 datepicker 实例。

我将控制器中的所有日期选择器代码放入一个命名空间中：

$scope.datePicker = (function () {
    var method = {};
    method.instances = [];

    method.open = function ($event, instance) {
        $event.preventDefault();
        $event.stopPropagation();

        method.instances[instance] = true;
    };

    method.options = {
        'show-weeks': false,
        startingDay: 0
    };

    var formats = ['MM/dd/yyyy', 'dd-MMMM-yyyy', 'yyyy/MM/dd', 'dd.MM.yyyy', 'shortDate'];
    method.format = formats[0];

    return method;
}());

然后使用以下标记：

<p class="input-group">
    <input type="text" class="form-control" ng-model="editableEmployee.dateHired" datepicker-popup="{{datePicker.format}}" datepicker-options="datePicker.options" is-open="datePicker.instances['dateHired']" close-text="Close" />
    <span class="input-group-btn">
        <button type="button" class="btn btn-default" ng-click="datePicker.open($event, 'dateHired')"><i class="glyphicon glyphicon-calendar"></i></button>
    </span>
</p>

<p class="input-group">
    <input type="text" class="form-control" ng-model="editableEmployee.dateFired" datepicker-popup="{{datePicker.format}}" datepicker-options="datePicker.options" is-open="datePicker.instances['dateFired']" close-text="Close" />
    <span class="input-group-btn">
        <button type="button" class="btn btn-default" ng-click="datePicker.open($event, 'dateFired')"><i class="glyphicon glyphicon-calendar"></i></button>
    </span>
</p>

这对我来说就像一个魅力。

于 2015-02-05T15:59:28.897 回答
10

这应该有效（不同的模型、打开标志和功能）：

<div>
        <div class="form-horizontal pull-left">
            <input type="text" datepicker-popup="dd-MMMM-yyyy" ng-model="dt1" is-open="opened1" min="minDate" max="'2015-06-22'" datepicker-options="dateOptions" date-disabled="disabled(date, mode)" ng-required="true"/>
            <button class="btn" ng-click="open1()"><span class="glyphicon glyphicon-calendar"></span></button>
        </div>
        <div class="form-horizontal pull-left">
            <input type="text" datepicker-popup="dd-MMMM-yyyy" ng-model="dt2" is-open="opened2" min="minDate" max="'2015-06-22'" datepicker-options="dateOptions" date-disabled="disabled(date, mode)" ng-required="true" />
            <button class="btn" ng-click="open2()"><span class="glyphicon glyphicon-calendar"></span></button>
        </div>
        <button type="submit" class="btn btn-default">Submit</button>
    </div>

和内部控制器：

   $scope.open1 = function($event) {
    $event.preventDefault();
    $event.stopPropagation();

    $scope.opened1 = true;
  };

   $scope.open2 = function($event) {
    $event.preventDefault();
    $event.stopPropagation();

    $scope.opened2 = true;
  };
于 2014-01-04T07:20:54.583 回答
1

这对我有用：$id 是范围 id，由 angular 提供。

    ctrl.opened = {};
    ctrl.openDatatimePicker = function ($event, id) {
        $event.preventDefault();
        $event.stopPropagation();
        ctrl.opened[id] = true;
    }
                                            <input type="text" 
                                                   class="form-control" 
                                                   uib-datepicker-popup="{{vm.datepickerFormat}}"
                                                   ng-model="x.FraDato" 
                                                   is-open="vm.opened[$id]"
                                                   datepicker-options="vm.datepickerOptions"
                                                   ng-required="true" 
                                                   ng-click="vm.openDatatimePicker($event,$id)"/>

于 2017-03-06T14:02:17.803 回答
0

不需要额外的更改。只要您将每个日期输入包装在它自己的控制器 div 中，范围就会与该输入一起驻留

例子：

<div ng-controller="DatepickerDemoCtrl">
    <div class="form-horizontal pull-left">
        <input type="text" datepicker-popup="dd-MMMM-yyyy" ng-model="dt" is-open="opened" min="minDate" max="'2015-06-22'" datepicker-options="dateOptions" date-disabled="disabled(date, mode)" ng-required="true"/>
        <button class="btn" ng-click="open($event)"><span class="glyphicon glyphicon-calendar"></span></button>
    </div>
</div>
<div ng-controller="DatepickerDemoCtrl">
    <div class="form-horizontal pull-left">
        <input type="text" datepicker-popup="dd-MMMM-yyyy" ng-model="dt" is-open="opened" min="minDate" max="'2015-06-22'" datepicker-options="dateOptions" date-disabled="disabled(date, mode)" ng-required="true" />
        <button class="btn" ng-click="open($event)"><span class="glyphicon glyphicon-calendar"></span></button>
    </div>
</div>
于 2014-07-03T22:27:04.060 回答
0

虽然这是一个古老的问题，但对于和我遇到同样问题的人来说却是答案。

我将 datepicker onfocus 分配给该元素，效果很好。示例代码。

   $(document).on('focus','.datepicker',function(){
        $(this).datepicker();
   });
于 2015-05-27T11:14:49.383 回答
0

可以在单个页面上打开 ui-bootstrap 的多个日期选择器

JS

  $scope.open = {};
  $scope.openCalendar = function (e, date) {
    e.preventDefault();
    e.stopPropagation();

    if ($scope.open[date] === true) {
      $scope.open = {};
    } else {
      $scope.open = {};
      $scope.open[date] = true;
    }
  };

HTML

<input type="text" id="created1" name="created1" datetime-picker="" datepicker-options="dateOptions" timepicker-options="timeOptions" ng-click="openCalendar($event, 'created1')" placeholder="0000/00/00 00:00" is-open="open.created1" autocomplete="off" class="form-control" ng-model="vm.condition.created1">

<input type="text" id="created2" name="created2" datetime-picker="" datepicker-options="dateOptions" timepicker-options="timeOptions" ng-click="openCalendar($event, 'created2')" placeholder="0000/00/00 00:00" is-open="open.created2" autocomplete="off" class="form-control" ng-model="vm.condition.created2">
于 2018-12-10T02:14:37.527 回答