我有一个结构记录数组和一个记录insert
函数insert or update
。
insert
函数获取(list
记录数组)、(name
书名)author
、、、和大小year
copies
n
list
如果找到记录,则更新记录,否则插入新记录。这里n=7
void insert(struct books *list,char name[],char author[],int year,int copies,int n)
{
int i,found=0,empty;
for(i=0;(i<n) && (found==0);i++)
{
// update works fine
if( strcmp(name,list[i].name)==0 && strcmp(author,list[i].author)==0 )
{
list[i].copies=copies;
list[i].year=year;
printf("\n\n####################################################\n");
printf("####\tRecord was successfully updated!\t####\n");
printf("####################################################\n");
found=1;
}
//get an empty record
if(strcmp(list[i].author,"i")==0){empty=i;}
}
//insert gives segmentation error
if(found==0)
{
strcpy(list[empty].name,name);
strcpy(list[empty].author,author);
list[empty].year=year;
list[empty].copies=copies;
printf("\n\n####################################################\n");
printf("####\tRecord was successfully inserted!\t####\n");
printf("####################################################\n");
}
}
我的list
数组是:
A
Ruby On Rails
2004
100
B
Inferno
1993
453
C
Harry Potter and the soccers stones
2012
150
D
Harry Potter and the soccers stone
2012
150
E
Learn Python Easy Way
1967
100
F
Ruby On Rails
2004
130
i
i
0
0
为什么要给Segmentation error: 11
?