0

该程序旨在通过匹配左括号和右括号来错误检查其他源文件。因为我想在每次检查代码时使用该程序，所以我创建了一个数组来存储通过扫描仪输入的代码行，然后有一个方法将其转换为字符串，但是当我尝试存储新字符串并将其传递给另一个方法，该方法将把它拆开并检查左大括号和右大括号，它崩溃并且堆栈显示越界错误。我已尝试多次修复此问题，但我无法弄清楚导致它崩溃的原因。

这是我到目前为止所拥有的。我能得到任何帮助吗？

堆栈跟踪：

java.lang.ArrayIndexOutOfBoundsException: 1
at MatchUp.arrayToString(MatchUp.java:51)
at MatchUp.main(MatchUp.java:27)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at edu.rice.cs.drjava.model.compiler.JavacCompiler.runCommand(JavacCompiler.java:272)

import java.io.*;
import java.util.Scanner;

public class braceMatchup{
public static void main(String[] args) throws IOException{


  Scanner nameDoc = new Scanner(System.in);                              
  System.out.println("Please enter the file name:");
  String fileName = nameDoc.next();                                                        
  File validation = new File(fileName);

  while (!validation.exists()){                                           
    System.out.println("Please enter a valid file name:");
    fileName = nameDoc.next();
    validation = new File(fileName);
  }

  nameDoc.close();

  Scanner doc = new Scanner(new FileReader(fileName));                    
  arrayToString(doc);  
}


public static void arrayToString(Scanner doc){

  for(int tLines = 0; doc.hasNextLine(); tLines++){
    String lines[] = {doc.nextLine()};

    for(int pLines = 0; pLines <= tLines; pLines++){
        String arrayLine = lines[pLines].toString();

        walkArray(arrayLine, tLines);}
    }
}

public static void walkArray(String arrayLine, int tLines){
 int index;            

  for (int i = 0; i <= arrayLine.length(); i++){
    if (arrayLine.substring(i) == "{" || arrayLine.substring(i) == "}")
      index = i;
    else
      index = arrayLine.length();

    bracketCount(arrayLine, index);
  }
}


public static void bracketCount(String arrayLine, int index){

  int openCount = 0; 
  int closeCount = 0;          


  if(arrayLine.substring(index) == "{"){
    openCount++;

    if (index != 0){
      String formatLine = arrayLine.substring(0, index -1); //lines[pLines].indexOf('{')
      System.out.println(formatLine.trim() + " " + "(" + openCount + ")" + "{");}

      else if(index == 0){
        String formatLine = arrayLine.substring(index); //arrayLine.indexOf('{')
        System.out.println(formatLine.trim() + " " + "(" + openCount + ")" + "{");
      }
      else if(arrayLine.substring(index) == "}"){
        closeCount++;

        if(openCount > closeCount)
          closeCount = openCount - 1;
        else if(closeCount > openCount)
          closeCount = 0; 

      if(index != 0){
        String formatLine = arrayLine.substring(0, index - 1); //arrayLine.indexOf('{')
        System.out.println( formatLine.trim() + " " + "}" + "(" + closeCount + ")");
      }
      else if (index == 0){
        String formatLine = arrayLine.substring(0, index - 1); //arrayLine.indexOf('{')
        System.out.println( formatLine.trim() + " " + "}" + "(" + closeCount + ")");}
      }
      else
        System.out.println(arrayLine);
    }
  }
}
4

1 回答 1

1

没有看到错误跟踪，这很难..但是看着@

public static void arrayToString(Scanner doc){

for(int tLines = 0; doc.hasNextLine(); tLines++){
  String lines[] = {doc.nextLine()}; // SINGLE ELEMENT ARRAY

  for(int pLines = 0; pLines <= tLines; pLines++){
      String arrayLine = lines[pLines].toString(); // if pLines > 0, you'll be sad

      walkArray(arrayLine, tLines);}}}

访问时最有可能出现问题lines[pLines]。我不知道你的逻辑在尝试什么（我没有读那么远......只是做了一个代码审查），所以你可能应该重新评估这一点。

于 2013-10-26T20:05:47.833 回答