该文件由 ajax 请求调用。结果来到这里我想在调用函数中放入两个不同的地方。
<?php
//Some processing gives $text
$s=nl2br($text);
$data['x'] = $p;
$data['y'] = $q;
//Start from here
echo "<b>Positive count : $x with $p % </b>"; echo "</br>";
echo "<b>Negative count : $y with $q % </b>"; echo "</br>";
echo "</br>";
echo "Page content : ";
echo "</br>";
echo "</br>";
echo $s;
//End. This content should be place in <div1>. Want to send this as a json string
和
//Start from here
echo "First 5 post";
$result = mysqli_query($con,"select post from facebook_posts where p_id > (select MAX(p_id) - 5 from facebook_posts)");
while ($row = $result->fetch_array(MYSQLI_ASSOC))
{
echo $row['post'];
echo '<br/>';
}
//End. This content should be placed in <div2> Want to send this as a json string
如果有单个变量,那么我们可以使用以下方法轻松完成:
$resultArray = array("resultOne" => $result1,"resultTwo" => $result2);
echo json_encode($resultArray);
在接收端:
document.getElementById("myFirstDiv").innerHTML=xmlhttp.responseText.resultOne;
document.getElementById("mySecondDiv").innerHTML=xmlhttp.responseText.resultTwo;
但是如何将上述复杂结果放入 json 变量中?