嗨,我正在尝试使用 ajax 将简单的用户名和密码发送到 login.php,这将返回 2 结果为假或真。问题是,当我单击#loginbutton 时,它似乎正在加载,但之后什么都没有出现(没有警报或页面重新加载)。
这是我的脚本
<script>
$(document).ready(function(){
$('#loginbutton').click(function() {
$('#loginform').submit(function() { // catch the form's submit event
$.ajax({ // create an AJAX call...
data: $(this).serialize(), // get the form data
type: $(this).attr('method'), // GET or POST
url: $(this).attr('action'), // the file to call
success: function(result) { // on success..
if (result == 'false') {
alert("Login failed.\n\nThe username and password doesn't match or perhaps the username doesn't exist.\n\nMake sure you have checked your email and validate your account.");
}
else if (result == 'true') {
alert("Thank you, the registration was successful. \nWe have sent you an email, please validate your account. \nClick OK and we will redirect you to the homepage.");
window.location.replace("http://127.0.0.1/wordpress/");
}
}
});
return false; // cancel original event to prevent form submitting
});
});
});
</script>
和我的登录表单(我正在尝试将其与 wordpress 集成)
<?php
$templateDirectory= get_bloginfo('template_directory');
echo'
<form id="loginform" action="'.$templateDirectory.'/login.php" method="post" class="login">
<a href="#" onClick="document.getElementById(\'loginform\').submit();" class="linkit">LOGIN</a>
<div class="para"><input type="text" name="uname" placeholder="Username ..." onkeydown="if (event.keyCode == 13) document.getElementById(\'loginform\').submit()"> <br><input type="password" name="pass" placeholder="Password ..." onkeydown="if (event.keyCode == 13) document.getElementById(\'loginform\').submit()"></div>
</form>';
?>
任何人都可以告诉我出了什么问题:(