javascript - 在 Twitter Bootstrap 3 中对齐导航

Question

由于用于对齐导航的 Bootstrap 示例对我不起作用，因此我尝试构建自己的水平对齐导航。代码如下所示：

<div class="row">
    <div class="col-lg-12">
        <ul id="navigation">
             <li class=""><a href="#">One</a></li>
             <li class=""><a href="#">Two</a></li>
             <li class=""><a href="#">Three</a></li>
             <li class=""><a href="#">Four</a></li>
             <li class=""><a href="#">Five</a></li>
             <li class=""><a href="#">Six</a></li>
             <li class=""><a href="#">Seven<</a></li>
             <li class="stretch"></li>
        </ul>
    </div>
</div>

使用的 CSS：

#navigation {
    list-style-type: none;
    text-align: justify;
    height: 21px;
    background: #ccc
}

#navigation li {
    display: inline
}

#navigation .stretch {
    display: inline-block;
    width: 100%;

    /* if you need IE6/7 support */
    *display: inline;
    zoom: 1
}

当导航一开始就存在时，就像静态代码一样，一切看起来都很好。当我的应用程序动态创建导航时，稍后会插入链接。那么这个理由就不起作用了。

怎么解决？

Answer 1

检查这个小提琴链接http://jsfiddle.net/Mohinder/PAvnp/

用你的 Bootstrap CSS 添加这个 HTML 和 CSS 并检查，我刚刚为你做了。

这是HTML

<div class="row">
    <div class="col-lg-12">
        <ul id="navigation">
             <li class=""><a href="#">One</a></li>
             <li class=""><a href="#">Two</a></li>
             <li class=""><a href="#">Three</a></li>
             <li class=""><a href="#">Four</a></li>
             <li class=""><a href="#">Five</a></li>
             <li class=""><a href="#">Six</a></li>
             <li class=""><a href="#">Seven</a></li>
        </ul>
    </div>
</div>

这是CSS

#navigation {float:none; text-align:center; display:table; list-style:none; width:100%; }
#navigation li { float:none; display:table-cell; }
#navigation li a { display:block; line-height:20px; margin:0px 5px; }

Answer 2

如果您想利用Bootstrap 的预建类，我相信这就是您想要的。

   <div class="row">
        <div class="col-lg-12">
            <table id="navigation" class="table">
                 <td class="text-center"><a href="#">One</a></td>
                 <td class="text-center"><a href="#">Big</a></td>
                 <td class="text-center"><a href="#">Jump</a></td>
            </table>
        </div>
    </div>

Answer 3

我已经设法让合理的导航栏与崩溃一起工作。

html:

 <nav class="navbar navbar-default" role="navigation">
  <!-- Brand and toggle get grouped for better mobile display -->
  <div class="navbar-header">
<button type="button" class="navbar-toggle" data-toggle="collapse" data-target="#bs-example-navbar-collapse-1">
  <span class="sr-only">Toggle navigation</span>
  <span class="icon-bar"></span>
  <span class="icon-bar"></span>
  <span class="icon-bar"></span>
</button>
  </div>

  <!-- Collect the nav links, forms, and other content for toggling -->
  <div class="collapse navbar-collapse" id="bs-example-navbar-collapse-1">
    <ul class="nav nav-justified">
          <li class="active"><a href="#">Home</a></li>
          <li><a href="#">Projects</a></li>
          <li><a href="#">Services</a></li>
          <li><a href="#">Downloads</a></li>
          <li><a href="#">About</a></li>
          <li><a href="#">Contact us</a></li>
        </ul>


  </div><!-- /.navbar-collapse -->
</nav>

CSS：

  .navbar-collapse {
  padding-left: 0px;
  padding-right: 0px;
}
 .nav-justified {
  background-color: #;
  border-radius: 0px;
  border: 0px solid #;
}
 .nav-justified > li > a {
  margin-bottom: 0;
  padding-top: 15px;
  padding-bottom: 15px;
  color: #;
  font-weight: ;
  text-align: center;
  border-bottom: 0px  #;
  background-color: #; /* Old browsers */
  background-repeat: repeat-x; /* Repeat the gradient */
  background-image: -moz-linear-gradient(top, # 0%, # 100%); /* FF3.6+ */
  background-image: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#f5f5f5), color-stop(100%,#e5e5e5)); /* Chrome,Safari4+ */
  background-image: -webkit-linear-gradient(top, #f5f5f5 0%,#e5e5e5 100%); /* Chrome 10+,Safari 5.1+ */
  background-image: -o-linear-gradient(top, #f5f5f5 0%,#e5e5e5 100%); /* Opera 11.10+ */
  filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#f5f5f5', endColorstr='#e5e5e5',GradientType=0 ); /* IE6-9 */
  background-image: linear-gradient(top, #f5f5f5 0%,#e5e5e5 100%); /* W3C */
}
 .nav-justified > .active > a,
 .nav-justified > .active > a:hover,
 .nav-justified > .active > a:focus {
  background-color: #ddd;
  background-image: none;;
}
 .nav-justified > li:first-child > a {
  border-radius: 5px 5px 0 0;
}
 .nav-justified > li:last-child > a {
  border-bottom: 0;
  border-radius: 0 0 5px 5px;
}

@media (min-width: 768px) {
 .nav-justified {
  max-height: 52px;
}
 .nav-justified > li > a {
  border-left: 1px solid #fff;
  border-right: 1px solid #d5d5d5;
}
 .nav-justified > li:first-child > a {
  border-left: 0;
  border-radius: 5px 0 0 5px;
}
 .nav-justified > li:last-child > a {
  border-radius: 0 5px 5px 0;
  border-right: 0;
}
}
 @media (max-width: 768px) {
 .navbar {
  border-radius: 5px;
}
}
 @media screen and (max-width: 550px) {
 .navbar {
  border-radius: 5px;
}
}

Answer 4

您必须在 li 中使用“float:left”