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我有一个通过 AJAX 提交并上传文件的表单。但是，尽管文件已正确上传，但 javascriptINTERNAL SERVER ERROR在上传后显示。我知道文件已添加到数据库并上传到服务器；除了此错误消息外，一切似乎都按预期工作。Django 日志中似乎没有错误消息。

我也没有编写处理 javascript 的代码，因此实际上可能有更好的方法来执行此操作，或者我忽略了一些明显的方法。

似乎由于这一行而发生错误：

response = JSONResponse(data, {}, response_mimetype(self.request))

在我的views.py中：

def response_mimetype(request):
    if "application/json" in request.META['HTTP_ACCEPT']:
        return "application/json"
    else:
        return "text/plain"

class UploadedFileCreateView(CreateView):
    model = UploadedFile
    form_class = UploadedFileForm

    def form_valid(self, form):
        self.object = form.save(commit=False)
        self.object.project_id = self.kwargs['proj_key']
        self.object.save()
        f = self.request.FILES.get('file')

        data = [{
            'name': self.object.name(),
            'url': "/uploads/xmlfiles/" + self.object.name().replace(" ", "_"),
            'delete_url': reverse('fileupload:upload-delete',
                kwargs={'pk':self.object.id,
                'proj_key':self.kwargs['proj_key']}),
            'delete_type': "DELETE"}]


        # the problem line
        response = JSONResponse(data, {}, response_mimetype(self.request)) 
        response['Content-Disposition'] = 'inline; filename=files.json'
        return super(UploadedFileCreateView, self).form_valid(form)

    def get_context_data(self, **kwargs):
        context = super(UploadedFileCreateView, self).get_context_data(**kwargs)
        context['files'] = UploadedFile.objects.all()
        context['proj'] = int(self.kwargs["proj_key"])
        return context

class JSONResponse(HttpResponse):
    """JSON response class."""
    def __init__(self,obj='',json_opts={},mimetype="application/json",*args,**kwargs):
        content = simplejson.dumps(obj,**json_opts)
        super(JSONResponse,self).__init__(content,mimetype,*args,**kwargs)

我认为问题可能出在reverse方法上，但那里一切正常。以防万一，这是来自 urls.py 的行：

(r'^projects/(?P<proj_key>\d+)/d/(?P<pk>\d+)$', UploadedFileDeleteView.as_view(), {}, 'upload-delete'),

以及相关型号：

class UploadedFile(models.Model):
    """This represents a file that has been uploaded to the server."""
    STATE_UPLOADED = 0
    STATE_ANNOTATED = 1
    STATE_PROCESSING = 2
    STATE_PROCESSED = 4
    STATES = (
        (STATE_UPLOADED, "Uploaded"),
        (STATE_ANNOTATED, "Annotated"),
        (STATE_PROCESSING, "Processing"),
        (STATE_PROCESSED, "Processed"),
    )

    status = models.SmallIntegerField(choices=STATES,
        default=0, blank=True, null=True) 
    file = models.FileField(upload_to=settings.XML_ROOT)
    project = models.ForeignKey(Project)

    def __unicode__(self):
        return self.file.name

    def name(self):
        return os.path.basename(self.file.name)

    def save(self, *args, **kwargs):
        if not self.status:
            self.status = self.STATE_UPLOADED
        super(UploadedFile, self).save(*args, **kwargs)

    def delete(self, *args, **kwargs):
        os.remove(self.file.path)
        self.file.delete(False)
        super(UploadedFile, self).delete(*args, **kwargs)

编辑：刚刚在控制台中注意到这个 500 错误，但我不确定在哪里可以找到堆栈跟踪（因为我没有看到错误模板）：

[29/Oct/2013 23:38:56] "POST /upload/projects/1/ HTTP/1.1" 500 11939
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1 回答 1

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您需要将类的定义移到JSONResponse类之前UploadedFileCreateView；当尚未定义该类时，该错误发生在您调用该类之前。

该对象被保存，因为您在调用JSONReponse类之前已经保存了它：

def form_valid(self, form):
    self.object = form.save(commit=False)
    self.object.project_id = self.kwargs['proj_key']
    self.object.save() # object gets saved successfully here
    f = self.request.FILES.get('file')

    # ...


    # Here, JSONResponse is not defined yet, so this is resulting in a 500
    # since you have debug=False, its resulting in the default 500 error template
    # from your server.
    response = JSONResponse(data, {}, response_mimetype(self.request))
于 2013-10-28T05:17:28.090 回答