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我有一个这样的mysql表

id  Category         parent
2   Garments           12
3   Gents Garments          2
4   Sarees                  2
5   Bridal Sarees           4
6   IT                 12
7   IT Hardware         6
8   IT Software         6
9   Web Design          8
10  Web Based Solution  8
11  E-Commerce Solution 9
12  root                 NULL

使用 mysql 查询

SELECT t1.category AS lev1, t2.category as lev2, t3.category as lev3, 
t4.category as lev4
FROM categories AS t1
LEFT JOIN categories AS t2 ON t2.parent = t1.id
LEFT JOIN categories AS t3 ON t3.parent = t2.id
LEFT JOIN categories AS t4 ON t4.parent = t3.id
WHERE t1.category = 'root';

我能够得到这个结果

lev1    lev2       lev3            lev4
root    Garments  Gents Garments   NULL
root    Garments  Sarees       Bridal Sarees
root    IT    IT Hardware      NULL
root    IT    IT Software      Web Design
root    IT    IT Software      Web Based Solution

现在我找不到在树状结构中的单个列中获取值的方法。例子

root
--Garments
----Gents Garments
----Sarees
--IT
----IT Hardware
----IT Software
------Web Design
------Web Based Solution

使用以下查询修改的问题:

我已经部分实现了上述结果,但钢材需要使用以下查询进行适当的分组

SELECT distinct t1.category AS category
FROM categories AS t1
LEFT JOIN categories AS t2 ON t2.parent = t1.id
LEFT JOIN categories AS t3 ON t3.parent = t2.id
LEFT JOIN categories AS t4 ON t4.parent = t3.id
WHERE t1.category = 'root' 
union
SELECT distinct concat('--', t2.category) as category
FROM categories AS t1
LEFT JOIN categories AS t2 ON t2.parent = t1.id
LEFT JOIN categories AS t3 ON t3.parent = t2.id
LEFT JOIN categories AS t4 ON t4.parent = t3.id
WHERE t1.category = 'root'  
union

SELECT distinct  concat('----', t3.category) as category
FROM categories AS t1
LEFT JOIN categories AS t2 ON t2.parent = t1.id
LEFT JOIN categories AS t3 ON t3.parent = t2.id
LEFT JOIN categories AS t4 ON t4.parent = t3.id
WHERE t1.category = 'root' 
union
SELECT distinct concat('------', t4.category) as category
FROM categories AS t1
LEFT JOIN categories AS t2 ON t2.parent = t1.id
LEFT JOIN categories AS t3 ON t3.parent = t2.id
LEFT JOIN categories AS t4 ON t4.parent = t3.id
WHERE t1.category = 'root' 

我得到的结果是
root
--Garments
--IT
----Gents Garments
---- Sarees
----IT Hardware
----IT Software
------ Bridal Sarees
------Web设计
------基于Web的解决方案
但我想要像
root一样的结果
--Garments
----Gents Garments
---- Sarees
------ Bridal
Sarees --IT
----IT Hardware
-- --IT软件
------网页设计
------基于Web的解决方案

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1 回答 1

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如果您可以将表示层次结构的方式更改为传递闭包表,则可以利用我过去给出的几个答案。主题是如何控制查询输出的排序,就像你上面描述的那样。

于 2013-10-28T12:03:50.397 回答