-2

我们得到一个字符串数组，我们需要一个 char[]，即所有字符串中所有字符的数组 例如：

输入：[我，爱，你]

输出：[i, l, o, v, e, y, o, u]

首先，我制作了一个数组数组。

然后我找到了所需的 char[] 数组的长度。

到目前为止，我已经尝试了以下方法：

char[][] a1 = new char[str.length][];

for(int i =0;i<str.length;i++){
    a1[i]=str[i].toCharArray();
}

int total=0;
for(int i =0;i<str.length;i++){
    total = total + a1[i].length;
}

char[] allchar = new char[total];

for(int i=0;i<str.length;i++){
    //NOW HERE I WANT TO MERGE ALL THE char[] ARRAYS TOGETHER.
//HOW SHOULD I DO THIS?
}
4

6 回答 6

6 
String[] sArray = {"i", "love", "you"};
    String s = "";
    for (String n:sArray)
        s+= n;
    char[] c = s.toCharArray();
于 2016-07-06T17:14:53.410 回答
2

你可以这样做

char[] allchar = new char[total]; // Your code till here is proper

// Copying the contents of the 2d array to a new 1d array
int counter = 0; // Counter as the index of your allChar array
for (int i = 0; i < a1.length; i++) { 
    for (int j = 0; j < a1[i].length; j++) { // nested for loop - typical 2d array format
        allchar[counter++] = a1[i][j]; // copying it to the new array
    }
}
于 2013-10-25T16:37:54.707 回答
1

您可以执行以下方法。

    public void converter(String[] stringArray) {


    char[] charsInArray = new char[500];    //set size of char array    
    int counterChars = 0;

    for (int i = 0; i < stringArray.length; i++) { 

        int counterLetters = 0; //declare counter for for amount of letters in each string in the array 

        for (int j = 0; j < stringArray[i].length(); j++) { 


            // below pretty self explanatory extracting individual strings and a
            charsInArray[counterChars] = stringArray[i].charAt(counterLetters);

            counterLetters++;
            counterChars++;
        }
    }


    }
于 2013-10-25T17:33:12.333 回答
1 
String [] s = new String[]{"i", "love", "you"};

int length = 0;
for (int i = 0; i < s.length; i++) {        
    for (int j = 0; j < s[i].length(); j++) {
        length++;
    }
}

char [] c = new char[length];
int k = 0;
for (int i = 0; i < s.length; i++) {        
    for (int j = 0; j < s[i].length(); j++) {
        c[k] = s[i].charAt(j);
        k++;
    }
}
for (int j = 0; j < c.length; j++) {
    System.out.print("char is: " + c[j]);
}
于 2016-02-12T06:13:08.773 回答
0

在 Java 8 中，我们可以使用流。

public char[] convert(String[] words) {
    return Arrays.stream(words)
            .collect(Collectors.joining())
            .toCharArray();
}

Array.stream(T[] array)在这里，我们使用其中 T 是数组元素的类型从数组创建了一个流 。比我们使用Collectors.joining(). toCharArray()最后我们使用 String 的方法得到一个 char 数组。

于 2020-12-08T07:53:21.387 回答
0 
public static void main(String[] args)
{
    String sentence="Gokul Krishna is class leader";
    String[] array=sentence.split("\\s");
    int counter;
    //String word = new String();
    for(String word:array)
    {
        counter=0;
        char[] wordArray=word.toCharArray();
        for(int i=0;i<wordArray.length;i++)
        {
            counter++;
        }
        System.out.println(word+ " :" +counter);
    }
}
于 2019-01-19T02:40:21.460 回答