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I am new to java, and I am still learning, can anyone help in this respect in their spare time?I am trying to do a 10 page poem, just to start with.

I have created buttons that look like a number pad, I am trying to make this number work when it has been pressed/clicked. I am able to make the numbers show when pressed. However, where I am having problems is how to make this number open another layout I have created with a number.

Say I have created a layout and I want it to be page 7, how do I set it such that when number 7 is pressed (it shows the first line / title of the poem) and when the "Go" button is clicked, it opens the layout with poem number 7.

Thank you

EDIT

I followed what you told me and now I have one layout and one fragment class.

`<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="horizontal" >

<android.support.v4.view.ViewPager
    android:id="@+id/text_fragment_pager"
    android:layout_width="match_parent"
    android:layout_height="match_parent" />

<TextView
    android:id="@+id/tvpoem"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:textAppearance="?android:attr/textAppearanceMedium" />

`

and the fragment java class is like:
public class PoemMapFrag extends Fragment

`{  @Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {

    View view = inflater.inflate(R.layout.fragpoemsmap, container, false);
    TextView fragpageone = (TextView) view.findViewById(R.id.tvpoems);
    fragpageone.setText("Testing");
    return view;

}

public View onCreateView1(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.fragpoemsmap, container, false);
    TextView fragpagetwo = (TextView) view.findViewById(R.id.tvpoems);
    fragpagetwo.setText("Yawning");
    return view;
}

@Override
public void onActivityCreated(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onActivityCreated(savedInstanceState);
}`
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2 回答 2

1

处理按钮点击的方法是为其分配一个 OnClickListener，如下所示：

button.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View arg0) {
        //start a new activity or replace the Fragment in view
    }
};

对于您的特定情况，您可以使用Fragments显示每个页面，使用FragmentTransaction 替换 Fragment in view。如果您使用 Activity，您将有 10 个 OnCLickListeners（每页一个），所以我不建议这样做。

或者，您可以只使用滑动手势来切换 Fragment，从而摆脱您的按钮。ViewPager就是为此而设计的，您可以使用Jake Wharton 的 ViewPagerIndicator库来提供查看哪个页面的视觉反馈。

如果您需要我澄清某些事情，请不要犹豫；-)

编辑：根据您的要求，这是我使用片段的方法：

为每个页面创建一个片段。您每次都可以重复使用相同的布局，只包含一个带有页面文本的 TextView，宽度和高度设置为 match_parent。在片段的 onCreateView 中，您可以像这样获得对 textview 的引用：

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
    Bundle savedInstanceState) {

    View view = inflater.inflate(R.layout.fragment_page_layout, container, false);

    // Get references to layout elements
    pageTextView = (TextView) view.findViewById(R.id.article_paragraph_title);
    return view;
}

在 onActivityCreated 中：

pageTextView.setText(yourTextForThisPage);

在您的活动中，您可以设置一个按钮来切换页面，或者使用 ViewPager。主要思想是 Activity 将负责切换 Fragment，从而更改视图中的文本，因为每次更改 Fragment 时，都应该创建一个新的 Fragment 来替换之前的 Fragment。您可以使用我上面提供的链接来帮助您入门，或者按照THIS TUTORIAL，这似乎或多或少地实现了我试图解释的内容。我希望这能澄清一点......

于 2013-10-25T14:00:27.157 回答
0 
Button go = (Button) findViewById(R.id.BUTTON_ID);
go.setOnClickListener(new OnClickListener() {

    @Override
    public void onClick(View v) {
        Intent intent = new Intent(this, Poem_7.class)
        startActivity(intent)
    }
});
于 2013-10-25T13:55:58.040 回答