0

我有一个文本文件 output.txt，其内容每天都会更改，但格式总是如下所示：

Minimum text string length= 5
Maximum text string length= 22
Maximum numeric string would be only upto 2 digit before and after decimal.

输出.txt

OPERATINGSYSTEM SERVER1 SERVER2
Windows    1.36       4.42
Linux12    2.78       5.76
MacOS      3.45       6.39
Ubuntu      4.12       0.00
Android       0.00       3.46
FreePhysicalMemory    30.12      31.65
TotalVisibleMemorySize  48.00      48.00

我想让内容在列中正确排列和格式化为：

OPERATINGSYSTEM         SERVER1    SERVER2
Windows                  1.36       4.42
Linux12                  2.78       5.76
MacOS                    3.45       6.39
Ubuntu                   4.12       0.00
Android                  0.00       3.46
FreePhysicalMemory      30.12      31.65
TotalVisibleMemorySize  48.00      48.00

我在下面尝试过，但没有得到任何输出：

@ECHO OFF
SETLOCAL
SET "spaces=                         "
SET "OPERATINGSYSTEM=MacOS"
SET /a SERVER1=3.45
CALL :formatout
SET "OPERATINGSYSTEM=TotalVisibleMemorySize"
SET /a SERVER1=48.00
CALL :formatout
GOTO :EOF
:formatout
CALL :padright name 15
CALL :padleft size 11
ECHO +%OPERATINGSYSTEM %+%SERVER1%+%SERVER2%
GOTO :eof
:padright
CALL SET padded=%%%1%%%spaces%
CALL SET %1=%%padded:~0,%2%%
GOTO :eof
:padleft
CALL SET padded=%spaces%%%%1%%
CALL SET %1=%%padded:~-%2%%
GOTO :eof

编辑1

当output.txt如下：

OPERATINGSYSTEM           PROJECTSERVER1 PROJECTSERVER2
Windows        1.36           4.42
Linux12        2.78       5.76
MacOS       3.45       6.39
Ubuntu        4.12       0.00
Android       0.00       3.46
FreePhysicalMemory      30.12      31.65
TotalVisibleMemorySize       48.00      48.00
CPULoadPercentage        2           4

我正在尝试 t1 和 t2 中空间长度的所有可能组合，但没有得到完美的newoutput.txt文件：

OPERATINGSYSTEM     PROJECTSERVER1   PROJECTSERVER2
Windows                       1.36             4.42
Linux12                       2.78             5.76
MacOS                         3.45             6.39
Ubuntu                        4.12             0.00
Android                       0.00             3.46
FreePhysicalMemory           30.12            31.65
TotalVisibleMemorySize       48.00            48.00
CPULoadPercentage                2                4

我正在使用的代码：

@ECHO OFF &SETLOCAL
set "t1=                     "
set "t2=           "
(for /f "tokens=1-3" %%a in (Managed.txt) do (
set "v1=%%a%t1%"&set "v2=%t2%%%b"& set "v3=%t2%%%c"
call echo(%%v1:~0,25%%%%v2:~-14%%%%v3:~-14%%
))>newoutput.txt
4

3 回答 3

6

尝试：

@ECHO OFF &SETLOCAL
set "t1=                    "
set "t2=     "
(for /f "tokens=1-3" %%a in (output.txt) do (
    set "v1=%%a%t1%"&set "v2=%t2%%%b"& set "v3=%t2%%%c"
    call echo(%%v1:~0,25%%%%v2:~-8%%%%v3:~-8%%
))>out.txt

out.txt：

操作系统 SERVER1 SERVER2
视窗 1.36 4.42
Linux12 2.78 5.76
macOS 3.45 6.39
Ubuntu 4.12 0.00
安卓 0.00 3.46
免费物理内存 30.12 31.65
TotalVisibleMemorySize 48.00 48.00
于 2013-10-25T12:01:18.733 回答
2 
@echo off
    setlocal

    for /f "tokens=1-3" %%f in (output.txt) do call :formatOut %%f %%g %%h 

    endlocal
    exit /b

:formatOut
    setlocal
    set "spaces=                                     "
    set col1=%~1%spaces%
    set col1=%col1:~0,30%
    set col2=%spaces%%~2
    set col2=%col2:~-7%
    set col3=%spaces%%~3
    set col3=%col3:~-7%

    echo %col1% %col2% %col3% 

    endlocal
    goto :EOF

要生成文件输出，请调用 asformatData.cmd > finalFile.txt

于 2013-10-25T11:24:09.440 回答
0

从 GNU utils 安装 awk，并使用它（假设您的信息在文件“a”中）：

awk '{printf("%-24s %12s %12s\n",$1,$2,$3)}' a
于 2013-10-25T11:26:13.810 回答