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我正在尝试在我的字典中添加一些带有键的值，以将请求发布到服务器。我在 ios7 上没有问题，但在 ios5 中创建字典时遇到问题，当输入空值时，它不会插入该键或此后在字典中。这是我的代码示例

NSLog(@"name:%@, address:%@,city:%@, state:%@, country:%@, postal:%@ ,phone:%@,age:%@, gender:%@",self.pop.firstNameTextField.text,self.pop.addressTextField.text, self.pop.cityTextField.text,[NSNumber numberWithInt:stateId],[NSNumber numberWithInt:countryId],self.pop.postalCodeTextField.text,self.pop.phoneNumberTextField.text,self.pop.ageTextField.text,self.pop.genderTextField.text);


NSDictionary *details = [NSDictionary dictionaryWithObjectsAndKeys:
                          self.pop.firstNameTextField.text,@"name",
                          self.pop.addressTextField.text,@"address",
                          self.pop.cityTextField.text,@"city",
                          [NSNumber numberWithInt:stateId],@"state",
                          [NSNumber numberWithInt:countryId],@"country",
                          self.pop.postalCodeTextField.text,@"postalCode",
                          self.pop.phoneNumberTextField.text,@"phoneNo",
                          self.pop.ageTextField.text,@"age",
                          self.pop.genderTextField.text,@"gender",
                          nil];


NSLog(@"MyDetails:%@",details);

在 ios 7 中记录结果：

name: GamerLegend,address:india,city:, state:1, country:1, postal: ,phone:, age:, gender:
MyDetails:
{
    address = India;
    age = "";
    city = "";
    country = 1;
    gender = "";
    name = "GamerLegend";
    phoneNo = "";
    postalCode = "";
    state = 1;
}

ios5中的相同日志结果：

name: GamerLegend,address:haripad,city:(null), state:1, country:1, postal:(null) ,phone:(null), age:(null), gender:(null)
MyDetails:
{
    address = India;
    name = "GamerLegend";
}

我希望 ios5 的日志与 ios7 的日志相同。我做了一些搜索，我知道我可以事先比较该值以检查它是否为空，然后用空字符串添加到字典中。但这会很乏味。我想知道是否还有其他简单的解决方法。有没有更好的解决方案？

这是我目前的解决方案

-(void) checkForNull
{

    if([self.pop.firstNameTextField.text length] == 0)
        self.pop.firstNameTextField.text=@"";

    if([self.pop.addressTextField.text length] == 0)
        self.pop.addressTextField.text=@"";

    if([self.pop.cityTextField.text length] == 0)
        self.pop.cityTextField.text=@"";

    if([self.pop.postalCodeTextField.text length] == 0)
        self.pop.postalCodeTextField.text=@"";

    if([self.pop.phoneNumberTextField.text length] == 0)
        self.pop.phoneNumberTextField.text=@"";

    if([self.pop.ageTextField.text length] == 0)
        self.pop.ageTextField.text=@"18";

    if([self.pop.genderTextField.text length] == 0)
        self.pop.genderTextField.text=@"";
}
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1 回答 1

0

如果它符合您的要求，这应该可以工作：

创建一个 EXPECTED 键的数组。然后循环遍历它并将其与字典中 allKeys 方法的输出进行比较。如果那里缺少密钥，您可以使用空字符串、[NSNull null] 或任何浮动的内容添加缺少的密钥。（您当然需要使字典可变）。

像这样的东西：

for (NSString *expectedKey in allExpectedKeys) {
    BOOL keyMissing = YES;
    for (NSString *existingKey in [dictionary allKeys]) {

        if ([expectedKey isEqualToString:existingKey]) {
            keyMissing = NO;
            break;
        }
    }
    if (keyMissing) {
        [dictionary setObject:[NSNull null] forKey:expectedKey];
    }
}
于 2013-10-25T10:36:42.677 回答