我正在尝试调用 Web 服务来返回对象,但它会抛出错误
{"Message":"无法将类型 \u0027System.Int32\u0027 的对象转换为类型 \u0027System.Collections.Generic.IDictionary`2[System.String,System.Object]\u0027","StackTrace":" 在 System. Web.Script.Serialization.ObjectConverter.ConvertObjectToTypeInternal(Object o, Type type, JavaScriptSerializer 序列化器, Boolean throwOnError, Object& convertObject)\r\n 在 System.Web.Script.Serialization.ObjectConverter.ConvertObjectToTypeMain(Object o, Type type, JavaScriptSerializer 序列化器, Boolean throwOnError, Object&convertedObject)\r\n 在 System.Web.Script.Serialization.JavaScriptSerializer.Deserialize(JavaScriptSerializer 序列化程序, 字符串输入, 类型类型, Int32 depthLimit)\r\n 在 System.Web.Script.Serialization.JavaScriptSerializer .Deserialize[T](字符串输入)\r\n 在 System.Web.Script.Services。RestHandler.GetRawParamsFromPostRequest(HttpContext context, JavaScriptSerializer 序列化程序)\r\n 在 System.Web.Script.Services.RestHandler.GetRawParams(WebServiceMethodData methodData, HttpContext context)\r\n 在 System.Web.Script.Services.RestHandler.ExecuteWebServiceCall( HttpContext 上下文,WebServiceMethodData methodData)","ExceptionType":"System.InvalidOperationException"}
这是我的 javascript 示例
<script type="text/javascript">
$(function () {
$('#<%=ddlUserGroup.ClientID %>').change(function () {
UserGroupID = $('#<%= ddlUserGroup.ClientID %>').val();
$.ajax({
url: "WebService.asmx/GetMenu",
data: UserGroupID,
dataType: "json",
type: "POST",
contentType: "application/json; charset=utf-8",
success: function (result) {
var rootNode = $("#tree").dynatree("getRoot");
rootNode.removeChildren();
rootNode.addChild($.parseJSON(resp.Data));
},
error: function (jqXHR, textStatus, errorThrown) {
var loginUrl = jqXHR.getResponseHeader("loginUrl");
if (jqXHR.status == 502) {
window.location = loginUrl;
}
else {
alert('error' + errorThrown);
}
}
});
});
</script>
这是我的网络服务
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
[WebMethod]
public object GetMenu(int roleID)
{
var menuItems = new TblUserGroupMenuService().GetMenuByUserGroupID(Common.ToInt32(roleID));
List<TblmenuInfo> list = new List<TblmenuInfo>();
foreach (DataRow dr in menuItems.Rows)
{
list.Add(new TblmenuInfo
{
Id = Common.ToInt32(dr["ID"]),
Label = dr["Name"].ToString(),
// Url = dr["Url"].ToString(),
// Iconurl = dr["IconURL"].ToString(),
Parentid = Common.ToNInt32(dr["ParentID"]),
//Order = Common.ToInt32(dr["DisplayOrder"])
});
}
return list.AsHierarchy(o => o.Id, parent => parent.Parentid, orderBy => orderBy.Order).AsExtTreeNodes((o, children) => new ExtTreeNode<int>
{
Key = o.Id,
Title = o.Label,
Select = (o.Order < 9999),
IsFolder = children > 0
});
}