0

这是我应该编码的问题：

为一个函数 showCast 编写合约、文档字符串和实现，该函数接受电影标题并按照字符的字母顺序从给定电影中打印出具有相应演员/女演员的字符。列必须对齐（演员/女演员姓名前 20 个字符（包括角色姓名）。）如果找不到电影，则会打印出错误消息。

它举例说明了这里应该发生的事情

>>> showCast("Harry Potter and the Sorcerer's Stone")

Character           Actor/Actress

----------------------------------------

Albus Dumbledore    Richard Harris

Harry Potter        Daniel Radcliffe

Hermione Granger    Emma Watson

Ron Weasley         Rupert Grint



>>> showCast('Hairy Potter')

No such movie found

以下是我为同一个项目编写的其他函数，它们可能有助于回答这个问题。到目前为止，我必须做的一个总结是，我正在创建一个名为 myIMDb 的字典，其中包含电影标题的键和另一个字典的值。在该字典中，键是电影的角色，值是演员。我已经用它做了一些事情。myIMDb 是记录的全局变量。

其他函数，他们所做的是 docString

def addMovie (title, charList, actList):
    """The function addMovie takes a title of the movie, a list of characters,
    and a list of actors. (The order of characters and actors match one
    another.) The function addMovie adds a pair to myIMDb. The key is the title
    of the movie while the value is a dictionary that matches characters to
    actors"""

    dict2 = {}
    for i in range (0, len(charList)):
        dict2 [charList[i]] = actList[i]
    myIMDb[title] = dict2
    return myIMDb

我添加了三部电影，

addMovie("Shutter Island", ["Teddy Daniels", "Chuck Aule"],["Leonardo DiCaprio, ","Mark Ruffalo"])

addMovie("Zombieland", ["Columbus", "Wichita"],["Jesse Eisenberg, ","Emma Stone"])

addMovie("O Brother, Where Art Thou", ["Everett McGill", "Pete Hogwallop"],["George Clooney, ","John Turturro"])



def listMovies():
    """returns a list of titles of all the movies in the global variable myIMDb"""

    return (list(myIMDb.keys()))


def findActor(title, name):
    """ takes a movie title and a character's name and returns the
    actor/actress that played the given character in the given movie. If the
    given movie or the given character is notfound, it prints out an error
    message"""
    if title in myIMDb:
        if name in myIMDb[title]:
            return myIMDb[title][name]
        else:
            return "Error:  Character not in Movie"
    else:
        return "Error: No movie found"

现在我遇到了麻烦

我应该编写 showCast 函数，但我遇到了很多麻烦。我已经修补了一段时间，但是当我调用 myIMDb.values() 时，一切都会返回。而且我似乎无法遍历它来对它们进行排序以创建表格。

到目前为止，这是我想出的，但它并没有达到我的期望。我只是希望你们中的一个可以引导我朝着正确的方向前进。（注释掉的区域是我之前所做的，只是为了让你可以看到我的思路。[print(alist) 和 print(alist[0]) 只是为了确认它是列表中的一个大条目，而不是完全分开])

def showCast(title):

    if title in myIMDb:
        actList=[]
        chList=[]
        aList = myIMDb[title]
        print (aList)

          """"for i in range (len(aList)):
              if i%2==0:
                  chList.append(aList[i])
              else:
                  actList.append(aList[i])
          print(chList)
          print(actList)""""

else:
    return "Movie not Found"
4

2 回答 2

0

首先，我认为您不应该在addMovie函数中返回任何内容。只需简单地将其添加到全局变量中：

myIMDb = {}

def addMovie (title, charList, actList):
    global myIMDb

    """The function addMovie takes a title of the movie, a list of characters,
    and a list of actors. (The order of characters and actors match one
    another.) The function addMovie adds a pair to myIMDb. The key is the title
    of the movie while the value is a dictionary that matches characters to
    actors"""

    dict2 = {}
    for i in range (0, len(charList)):
        dict2 [charList[i]] = actList[i]
    myIMDb[title] = dict2

虽然我不建议经常使用全局变量，但我认为在这种情况下是可以原谅的：D

之后，在你的showCast函数中，我会使用这个：

def showCast(title):
    if title in myIMDb:
        actList=[]
        chList=[]
        movie = myIMDb[title]
        for character, cast in movie.keys(), movie.values(): #grab the character from
        #the keys, and cast from the values. 
              chList.append(character)
              actList.append(cast)

        print (chList, actList)
    else:
        return "Movie not Found"

这是我的输出：

['Columbus', 'Jesse Eisenberg, '] ['Wichita', 'Emma Stone']

它按预期工作，希望这会有所帮助！

于 2013-10-25T00:04:09.220 回答
-1

也许这些片段可以帮助您：

打印表格行

def printRow(character, actor):
    print(character + (20 - len(character)) * ' ' + actor))

对字符进行排序

def getSortedTitleList(titleList):
    sortedList = []
    characters = sorted(titleList)
    for character in characters:
        sortedList.append((character, titleList[character]))
    return sortedList

注意：我改为dict.keys().sort()兼容sorted(dict)Python 3。

于 2013-10-24T23:53:56.883 回答