25

尝试启动 celery worker 时出现导入错误。我不确定问题是什么。任何帮助将不胜感激。

我的项目：

email/__init__.py
    /celery.py

我尝试通过调用来运行应用程序：

celery worker --app=email

我已经按照这里的所有步骤 - http://docs.celeryproject.org/en/latest/getting-started/next-steps.html#about-the-app-argument

追溯：

File "/Users/.../bin/celery", line 9, in <module>
    load_entry_point('celery==3.0.24', 'console_scripts', 'celery')()
File "/Users/.../lib/python2.7/site-packages/celery/__main__.py, line 14, in main
main()
File "/Users/.../lib/python2.7/site-packages/celery/bin/celery.py", line 957, in main
cmd.execute_from_commandline(argv)
File "/Users/.../lib/python2.7/site-packages/celery/bin/celery.py", line 901, in execute_from_commandline
super(CeleryCommand, self).execute_from_commandline(argv)))
File "/Users/.../lib/python2.7/site-packages/celery/bin/base.py", line 185, in execute_from_commandline
argv = self.setup_app_from_commandline(argv)
File "/Users/.../lib/python2.7/site-packages/celery/bin/base.py", line 300, in setup_app_from_commandline
self.app = self.find_app(app)
File "/Users/.../lib/python2.7/site-packages/celery/bin/base.py", line 317, in find_app
return self.find_app('%s.celery:' % (app.replace(':', ''), ))
File "/Users/.../lib/python2.7/site-packages/celery/bin/base.py", line 311, in find_app
sym = self.symbol_by_name(app)
File "/Users/.../lib/python2.7/site-packages/celery/bin/base.py", line 322, in symbol_by_name
return symbol_by_name(name, imp=import_from_cwd)
File "/Users/.../lib/python2.7/site-packages/kombu/utils/__init__.py", line 80, in symbol_by_name
module = imp(module_name, package=package, **kwargs)
File "/Users/.../lib/python2.7/site-packages/celery/utils/imports.py", line 99, in import_from_cwd
return imp(module, package=package)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/importlib/__init__.py", line 37, in import_module
__import__(name)
ImportError: No module named celery

这是我的 celery.py

from __future__ import absolute_import

from celery import Celery
from app import mail

celery = Celery('email.celery', 
                broker = 'amqp://guest:guest@localhost:5672//',
                backend = 'amqp://')

if __name__ == '__main__':
    celery.start()

@celery.task
def send_email(nickname, email):
    mail.send(msg)
4

2 回答 2

48

问题是你在说“嘿兄弟，我听说你喜欢芹菜吃一些芹菜”。

但你真的应该说，“嘿，兄弟，我听说你安装了 celery，让我们创建一个名称非常相似的文件，这样我们就不会混淆我们的环境了”。

将您的email/celery.py文件重命名为email/celery_app.py

然后，当您启动您的工作人员时，请执行以下操作：

celery -A email worker --app=email.celery_app:app --loglevel=info # etc.

关键是你不需要在你的文件结构中命名celery.py文件，但如果你没有，那么你不能依赖 celery 来查找 celery，所以你必须通过手动指定 --app 来指向它。

于 2014-01-11T19:13:51.580 回答
23

我实际上遇到了类似的问题，假设您正在遵循Next Steps 教程，并且我所要做的就是从proj上面的目录运行 worker ，也就是说，假设您当前在proj目录中运行：

cd ..
celery -A proj worker -l info

它现在对我有用。

于 2014-08-14T19:31:37.490 回答