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我正在尝试将 will_paginate 用于要显示的项目列表。有一个带有下拉选项的表单，可以按状态获取对象。这是我的控制器

  def list
    @person = Person.find_by_id(session[:person_id])
                    params[:status] = params[:redirect_status] if params.has_key?('redirect_status')
                    @statuses = Peptide.statuses
                    @status = 'Not Ordered'
                    @status = params[:status] if params[:status] != nil || params[:status] == ''
                    @peptides = Peptide.find(:all, :conditions => ['status = ?', @status]).paginate(:per_page => 30, :page => params[:page])

    if Peptide.count.zero?
       flash[:notice] = "There are not any peptides entered"
       redirect_to :action => 'new'
    end#if zero
  end

这是在视图中 

  <form action="/peptide/create_spreadsheet_of_not_ordered" enctype="multipart/form-data" method="post">
  <table class="sortable" cellpading="5" cellspacing="2" width="100">
   <tr class= "header-line">
    <th>SS</th>
    <th>Status</th>
    <th>Peptide</th>
    <th>Gene</th>
    <th>Submitter</th>
    <th>Created</th>
    <th>Updated</th>
    <th>Sequence</th>
    <th>Modification</th>
    <th>Vendor</th>
</tr>
<% for @peptide in @peptides.reverse %>
<tr valign = "top" class= "<%= cycle('color_one', 'color_two') %>">
<!--an error here during development likely indicates that the people table has not be repopulated or
 that no submitter primer is present for a primer-->
    <td sorttable_customkey = 0 > <%=check_box_tag "box[]", @peptide.id %>
    <td><%= @peptide.status%></td>
    <td class><%= link_to @peptide.name, :action => :report, :id => @peptide.id %></td>
    <td><%= gene_links(@peptide.genes) rescue 'Error'%></td>
    <td><%= @peptide.submitter.name rescue "" %></td>
    <td <%= sorttable_customkey_from_date(@peptide.created_at)%> >
        <%= @peptide.created_at.strftime("%b %d %Y") rescue "Unknown"%>
    </td>
    <td <%= sorttable_customkey_from_date(@peptide.updated_at)%> >
        <%= @peptide.updated_at.strftime("%b %d %Y") rescue "Unknown"%>
    </td>
    <td><%= @peptide.sequence%></td>
    <td><%= @peptide.modifications%></td>
    <td><%= @peptide.vendor%></td>
        <%= buttons() %> 
</tr>
<%end%>

   <%= will_paginate @peptides %>
</table> 
<br> 
<%= submit_tag "Create Spreadsheet"%>

默认列表按排序状态分组。

但是，当我选择任何其他状态并提交表单时，分页链接会将我带回默认状态。请帮我解决这个问题。谢谢

4

1 回答 1

0

在没有看到视图的情况下，听起来您需要将当前params作为参数添加到其他状态的链接中......

更新

尝试将参数添加到您的状态链接：

<%= link_to @peptide.name, peptide_path(@peptide, params), :action => :report, :id => @peptide.id %>

文档在这里。

于 2013-11-05T17:14:47.113 回答