1

我有两张桌子：

CREATE TABLE "object_comment" 
("object_id" INTEGER PRIMARY KEY  NOT NULL, 
"object_comment_text" TEXT, 
"object_comment_title" TEXT, 
"object_comment_date" DATETIME)

和

CREATE TABLE "object_comment_mark" 
("object_id" INTEGER PRIMARY KEY  DEFAULT null, 
"object_comment_mark_value" FLOAT DEFAULT null, 
"object_comment_mark_date" DATETIME DEFAULT null)

我需要将它们与 object_id 字段连接起来，但唯一的行也应该出现在结果中。（有一些相等的 object_id 值我需要加入一行，一些 object_id 值不同，但它们应该在结果表中）

现在我有这个选择查询：

SELECT *
FROM object_comment
LEFT OUTER JOIN object_comment_mark ON object_comment.object_id = object_comment_mark.object_id

但在这种情况下，我没有第二个表中 object_id 具有唯一值的行。有什么帮助吗？

编辑：我需要什么

对象评论

1 | bla-bla | first | 2013
2 | be-be   | sec   | 2014

object_comment_mark

1 | 5 | 2013
4 | 3 | 2013

结果

1 |bla-bla | first| 2013 | 5 | 2013
2 | be-be  | sec  | 2014 |   |     
4 |        |      |      | 3 | 2013
4

2 回答 2

1

你想要的是完全外连接，SQLite 不支持。相反，您可以组合左连接和右连接的不匹配 (NULL) 记录。也不支持右连接，因此使用交换两个表的左连接：

SELECT oc.*, ocm.*
FROM object_comment AS oc
LEFT JOIN object_comment_mark AS ocm ON oc.object_id = ocm.object_id
UNION ALL
SELECT oc.*, ocm.*
FROM object_comment_mark AS ocm
LEFT JOIN object_comment AS oc       ON oc.object_id = ocm.object_id
WHERE oc.object_id IS NULL

或者，手动搜索不匹配的记录：

SELECT oc.*, ocm.*
FROM object_comment AS oc
LEFT JOIN object_comment_mark AS ocm ON oc.object_id = ocm.object_id
UNION ALL
SELECT NULL, NULL, NULL, NULL, *
FROM object_comment_mark
WHERE object_id NOT IN (SELECT object_id
                        FROM object_comment)
于 2013-10-24T12:14:45.093 回答
0

我不完全理解你的问题......

这是你需要的吗？

SELECT * FROM object_comment
INNER JOIN object_comment_mark ON object_comment.object_id = object_comment_mark.object_id
UNION ALL
SELECT *, NULL, NULL, NULL, NULL FROM object_comment
于 2013-10-24T10:51:49.320 回答