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我有自己的 RSS 提要，这里是：

  <?xml version='1.0' encoding='UTF-8'?>
  <rss xmlns:atom='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:blogger='http://schemas.google.com/blogger/2008' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0' version='2.0'>
  <channel>
  <atom:id>tag:blogger.com,1999:blog-2079382764445278058</atom:id>
  <lastBuildDate>Wed, 23 Oct 2013 18:38:23 +0000</lastBuildDate>
  <title>Whaaa</title>
  <description>Blog tests....</description>
  <link>http://whateverblog.blogspot.com/</link>
  <managingEditor>noreply@blogger.com (The author)</managingEditor>
  <generator>Blogger</generator>
  <openSearch:totalResults>1</openSearch:totalResults>
  <openSearch:startIndex>1</openSearch:startIndex>
  <openSearch:itemsPerPage>25</openSearch:itemsPerPage>
  <item>
  <guid isPermaLink='false'>tag:blogger.com,1999:blog-2079382764445278058.post-6231173351434517354</guid>
  <pubDate>Wed, 23 Oct 2013 13:15:00 +0000</pubDate>
  <atom:updated>2013-10-23T11:38:23.407-07:00</atom:updated>
  <title>Lorem ipsum</title>
  <description>span style="background-color: white; color: #444444; font-family: helvetica, arial, sans-serif; font-size: 16px; line-height: 20px;"&gt;Lorem ipsum dolor sit amet, consectetuer adipiscing elit, sed diam nonummy nibh euismod tincidunt ut laoreet dolore magna aliquam erat volutpat. Ut wisi enim ad minim veniam, quis nostrud exerci tation ullamcorper suscipit lobortis nisl ut aliquip ex ea commodo consequat. Duis autem vel eum iriure dolor in hendrerit in vulputate velit esse molestie consequat, vel illum dolore eu feugiat nulla facilisis at vero eros et accumsan et iusto odio dignissim qui blandit praesent luptatum zzril delenit augue duis dolore te feugait nulla facilisi.&lt;/span&gt;</description>
  <link>http://myblog.blogspot.com/2013/10/lorem-ipsum.html</link>
  <author>noreply@blogger.com (The Author)</author>
  <thr:total>0</thr:total>
  </item>
 </channel>
 </rss>

我有帖子的 html 模板，但我的问题是我不知道获取此信息的最佳方法是什么，将其复制并粘贴到 template.html....

你们有什么解决办法吗？

实现这一目标的最简单方法是什么？

////为了简短起见，让我们说我们只想要：

Published
Title
Description
Author

如何使用该信息创建 html 文档。例如：

firstpost.html（firstpost 是帖子标题的名称..）

<div id="title">Here Goes Post Title </div>
<divid="date">Here Goes Post Submission Date </div>
<div id="content"> Here Goes Post Description </div>
<div id="author"> Here goes Post Author </div>
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1 回答 1

0

例如具有如下功能：

function getRssFeed($feedString) {  

    $content = file_get_contents($feedString);  
    $x = new SimpleXmlElement($content);  

    echo "<ul>";  

    foreach($x->channel->item as $entry) {  
        echo "<li><a href='{$entry->link}' title='{$entry->title}'>" . $entry->title . "</a></li>";  
    }  
    echo "</ul>";  
}

您使用SimpleXmlElement解析非常简单的提要

于 2013-10-23T18:55:52.890 回答