-2

所以我有一个计算器应用程序。构建并且它可以正常工作但是如果用户输入例如 4+√ 我得到一个错误(如下所示)。有人告诉我,当用户点击 √ 按钮时,我需要查看用户是否已经输入了操作,如果他们已经输入了,那么就什么也不做。虽然我对 Java 很陌生,但我不知道该怎么做。

这是完成所有计算的动作侦听器(我相信代码需要在您看到 if (a.getSource() == textSqrt) 的位置下):

    public class event implements ActionListener {

    public void actionPerformed(ActionEvent a) {
        String text = a.getActionCommand();


        if (text.equals("1")) {
            result.setText(result.getText() + "1");
        } else if (text.equals("2")) {
            result.setText(result.getText() + "2");
        } else if (text.equals("3")) {
            result.setText(result.getText() + "3");
        } else if (text.equals("4")) {
            result.setText(result.getText() + "4");
        } else if (text.equals("5")) {
            result.setText(result.getText() + "5");
        } else if (text.equals("6")) {
            result.setText(result.getText() + "6");
        } else if (text.equals("7")) {
            result.setText(result.getText() + "7");
        } else if (text.equals("8")) {
            result.setText(result.getText() + "8");
        } else if (text.equals("9")) {
            result.setText(result.getText() + "9");
        } else if (text.equals("0")) {
            result.setText(result.getText() + "0");
        } else if (result.getText().indexOf(".") < 1){
            result.setText(result.getText() + "."); 
        }


        String str = result.getText();
        textBox = Double.parseDouble(str);

        if (a.getSource()
                == textAdd) {
            op = 1;
            firstInput = textBox;
            result.setText("");
        }

        if (a.getSource()
                == textSubtract) {
            op = 2;
            firstInput = textBox;
            result.setText("");
        }

        if (a.getSource()
                == textMultiply) {
            op = 3;
            firstInput = textBox;
            result.setText("");
        }

        if (a.getSource()
                == textDivide) {
            op = 4;
            firstInput = textBox;
            result.setText("");
        }

        if (a.getSource()
                == textPercent) {
            op = 5;
            firstInput = textBox;
            result.setText("");
        }

        if (a.getSource() == textSqrt) {
            op = 6;
            firstInput = textBox;
            answer = Math.sqrt(textBox);
            str = Double.toString(answer);
            result.setText(str);
        }

        if (a.getSource()
                == textSign) {
            double neg;
            op = 7;
            neg = 0 - textBox;
            str = Double.toString(neg);
            result.setText(str);
        }

        if (a.getSource()
                == textEqual) {
            if (op == 1) {
                answer = firstInput + textBox;
                str = Double.toString(answer);
                result.setText(str);
            } else if (op == 2) {
                answer = firstInput - textBox;
                str = Double.toString(answer);
                result.setText(str);
            } else if (op == 3) {
                answer = firstInput * textBox;
                str = Double.toString(answer);
                result.setText(str);
            } else if (op == 4) {
                answer = firstInput / textBox;
                str = Double.toString(answer);
                result.setText(str);
            } else if (op == 5) {
                answer = firstInput % textBox;
                str = Double.toString(answer);
                result.setText(str);
            }

        }
    }
}

这是我按下操作和平方根按钮时得到的错误

Exception in thread "AWT-EventQueue-0" java.lang.NumberFormatException: For input string: "."
    at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:1241)
    at java.lang.Double.parseDouble(Double.java:540)
    at inlab05.InLab05$event.actionPerformed(InLab05.java:215)
    at javax.swing.AbstractButton.fireActionPerformed(AbstractButton.java:2018)
    at javax.swing.AbstractButton$Handler.actionPerformed(AbstractButton.java:2341)
    at javax.swing.DefaultButtonModel.fireActionPerformed(DefaultButtonModel.java:402)
    at javax.swing.DefaultButtonModel.setPressed(DefaultButtonModel.java:259)
    at javax.swing.plaf.basic.BasicButtonListener.mouseReleased(BasicButtonListener.java:252)
    at java.awt.Component.processMouseEvent(Component.java:6505)
    at javax.swing.JComponent.processMouseEvent(JComponent.java:3321)
    at java.awt.Component.processEvent(Component.java:6270)
    at java.awt.Container.processEvent(Container.java:2229)
    at java.awt.Component.dispatchEventImpl(Component.java:4861)
    at java.awt.Container.dispatchEventImpl(Container.java:2287)
    at java.awt.Component.dispatchEvent(Component.java:4687)
    at java.awt.LightweightDispatcher.retargetMouseEvent(Container.java:4832)
    at java.awt.LightweightDispatcher.processMouseEvent(Container.java:4492)
    at java.awt.LightweightDispatcher.dispatchEvent(Container.java:4422)
    at java.awt.Container.dispatchEventImpl(Container.java:2273)
    at java.awt.Window.dispatchEventImpl(Window.java:2719)
    at java.awt.Component.dispatchEvent(Component.java:4687)
    at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:735)
    at java.awt.EventQueue.access$200(EventQueue.java:103)
    at java.awt.EventQueue$3.run(EventQueue.java:694)
    at java.awt.EventQueue$3.run(EventQueue.java:692)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDomain.java:76)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDomain.java:87)
    at java.awt.EventQueue$4.run(EventQueue.java:708)
    at java.awt.EventQueue$4.run(EventQueue.java:706)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDomain.java:76)
    at java.awt.EventQueue.dispatchEvent(EventQueue.java:705)
    at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:242)
    at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:161)
    at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:150)
    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:146)
    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:138)
    at java.awt.EventDispatchThread.run(EventDispatchThread.java:91)

抱歉发了这么长的帖子。希望有人可以帮助我:)

4

2 回答 2

1

检查是否存在“。” byindexOf('.') < 1是错误的。

如果'.'根本不存在,它会返回-1,但如果它存在于第一个字符中,它将返回0,两者都是 < 1 但意味着完全不同的东西。

于 2013-10-23T18:47:24.803 回答
0
java.lang.NumberFormatException: For input string: "."

根据解析器,单个句点不是有效数字。

弄清楚为什么那个明显出乎意料的输入会进入格式化程序。

使用==比较字符串是一个常见的错误。请改用该equals()方法。(确保您了解原因 - 在 SO 中搜索问题)。

于 2013-10-23T18:42:16.453 回答