sql - 从重复组中查找相交值？

Question

运行SQL Server 2012。考虑这个值集：

ID    Status
------------
11    0
11    1
11    2
12    0
12    1
12    2
13    1
14    2

如何检索按 ID 分组的相交状态值？

即因为ID=13only hasStatus=1并且ID=14only have Status=2，所以上面的数据将导致一个空行：

Status
------

但是，如果我们删除ID=14，结果将是：

Status
------
1

如果我们也删除ID=13，结果将是：

Status
------
0
1
2

更新

需要ID用任意数量的Status值来解决任意数量的问题。因此，两个SELECT查询是不够的（即使它可能适用于上面的测试数据）。

Answer 1

这是一个关系划分问题。

NOT EXISTS如果除以一个空集，则使用双重方法返回所有。

DECLARE @S TABLE (
  [ID] INT PRIMARY KEY)

INSERT INTO @S
VALUES      (11),
            (12)

SELECT DISTINCT [Status]
FROM   YourTable Y1
WHERE  NOT EXISTS(SELECT *
                  FROM   @S
                  WHERE  NOT EXISTS (SELECT *
                                     FROM   YourTable Y2
                                     WHERE  Y1.[Status] = Y2.[Status]
                                            AND Y2.ID = [@S].ID)) 

Answer 2

此选择应适用于任何值：

select distinct status
from a a1
where (select count(distinct id) from a) = (select count(distinct id) from a a2 where a2.status = a1.status)

这是一个完整的脚本，适用于您问题中的示例数字：create table a (id int, status int)

insert a values (11, 0)
insert a values (11, 1)
insert a values (11, 2)
insert a values (12, 0)
insert a values (12, 1)
insert a values (12, 2)
insert a values (13, 1)
insert a values (14, 2)

select distinct status
from a a1
where (select count(distinct id) from a) = (select count(distinct id) from a a2 where a2.status = a1.status)

delete a where id = 14

select distinct status
from a a1
where (select count(distinct id) from a) = (select count(distinct id) from a a2 where a2.status = a1.status)

delete a where id = 13

select distinct status
from a a1
where (select count(distinct id) from a) = (select count(distinct id) from a a2 where a2.status = a1.status)

Answer 3

我认为最简单（也是最易读）的方法是这样做：

select t.status
from Table1 as t
group by t.status
having count(distinct t.id) = (select count(distinct t2.id) from Table1 as t2)

sql fiddle demo