mysql - Mysql 5.5 /phpmyadmin 简单查询之谜

Question

如果我select在我的 PhpMyAdmin（版本 4.0.5）上运行这个查询：

(SELECT *
FROM prenotazione
WHERE stato = 'prenotato'
AND (to_days( data ) +2) < to_days( NOW( ) )
)

运行良好。

但是，如果我运行一个delete不起作用的查询：

(DELETE *
FROM prenotazione
WHERE stato = 'prenotato'
AND (to_days( data ) +2) < to_days( NOW( ) )
)

有人请解释一下，为什么会这样。

score 4 · Accepted Answer

只是

DELETE FROM ...

不是

DELETE * FROM ...
      ^^^

有关详细信息，请参阅DELETE 语法

score 1 · Accepted Answer

像这样进行查询：

(DELETE FROM prenotazione WHERE stato = 'prenotato' AND (to_days( data ) +2) < to_days( NOW( ) ) )

有关更多信息，请查看删除语法手册

score 0 · Accepted Answer

这项工作在查询前后没有 * 和括号

DELETE
FROM prenotazione
WHERE stato = 'prenotato'
AND (to_days( data ) +2) < to_days( NOW( ) )

3 回答 3